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3 years ago

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Ravi sold 1/5 of his apples. He gave his friend 2/5 of the remainder. Ravi remained with 60. How many apples did ravi have at fi

rst

1 answer:

zheka24 [161]3 years ago

8 0

Answer:

The number of Apples did Ravi have at first is 125 .

Step-by-step explanation:

Let the number of Apples did Ravi have at first = x

The Apples which is sold by Ravi = $\frac{1}{5}$ of x

So, remainder now = x - $\frac{1}{5}$ of x = $\frac{4}{5}$ of x

The apples given to his friend = $\frac{2}{5}$ of $\frac{4}{5}$ x

I.e The apples given to his friend = $\frac{8}{25}$ of x

Now, The remaining Apples did Ravi have = 50

∴ According to question

$\frac{4}{5}$ of x - $\frac{8}{25}$ of x = 60

Or, $\frac{20-8}{25}$ of x = 60

Or, $\frac{12}{25}$ of x = 60

∴ x = $\frac{25\times 60}{12}$ = 125

Hence The number of Apples did Ravi have at first is 125 . Answer

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Step-by-step explanation:

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$\begin{array}{cccccc}{Class} & {51-58} & {59-66} & {67-74} & {75-82} & {83-90} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}$

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$\begin{array}{cccccc}{x} & {54.5} & {62.5} & {70.5} & {78.5} & {86.5} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}$

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This is calculated as:

$s^2 =\frac{\sum (x - \overline x)^2}{\sum f - 1}$

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$s^2 =\frac{(54.5-68.9)^2+(62.5-68.9)^2+(70.5-68.9)^2+(78.5-68.9)^2+(86.5-68.9)^2}{37 - 1}$

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