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goldenfox [79]
2 years ago
13

Solve for x.

Mathematics
1 answer:
alexandr402 [8]2 years ago
7 0

this is how i calculated for x!

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Answer:

question 1 = x7 and question 2 = 24x^3+56x^2 I'm pretty sure

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Emily is taking her motorized scooter to a friend's house which is 96 miles away she is riding at an average rate of 15 miles pe
S_A_V [24]
It would take Emily a little over 6 hours to get to her friends house.
3 0
3 years ago
Find x if the average of 20,20,19,13 and x is 16
amid [387]
16 times the quantity of numbers, in this case 5, which = 80, then subtract each number, 80-20-20-19-13=8.  X should = 8
4 0
3 years ago
Read 2 more answers
Help plead i dont get this
professor190 [17]
Find the percent of the circle

r=radius of circle
then r=1/2 of the diagonal of the square
use some pythagoran theorme

45,45,90 triangle
(r√2)/2=1/2 of a side
r√2 is one side
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2r²=square

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percent it is is

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0.636
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8 0
4 years ago
B is the midpoint of AC. If Ab= x +5 and BC = 2x-11, find the measure of Ab.
LuckyWell [14K]

__________________________

Measurement of "AC" :

(x + 5) + (2x <span>− 11) ;
________________________

Find the measurement of "AB" [which is: "(x+5)" ]: 
______________________________________________
First, simplify to find the measurement of "AC" :
________________________________________
 </span>(x + 5) + (2x − 11) ;

=  (x + 5) + 1(2x − 11) ;

=   x + 5 + 2x − 11 ;

 → Combine the "like terms" ; 

   x + 2x = 3x ;
   
   5 − 11 = - 6 ;
______________
to get:  3x − 6 ; 
_______________
So,  (x + 5) + (2x − 11) =  3x − 6 ;
_______________________________
Solve for:  "(x + 5)"
_______________________________

We have: 
_______________________________

(x + 5) + (2x − 11) =  3x − 6  ;

Subtract:  "(2x − 11)" ;  from EACH SIDE of the equation ;
                                      to isolate "(x + 5)" on one side of the equation; 
                                      and to solve for "(x + 5)" ;
________________________________________________________
    →  (x + 5) + (2x − 11) − (2x − 11) =  (3x − 6) − (2x − 11) ;
  
         → (x + 5)  = (3x − 6) − (2x − 11) ;
_________________________________________________
  Note:  Simplify:  "(3x − 6) − (2x − 11)" ;

     →  (3x − 6) − (2x − 11)  ;
 
         =  (3x − 6) − 1(2x − 11) ;
 
         =   3x − 6 − 2x + 11 ;
__________________________
   →  Combine the "like terms" :
_____________________________
         +3x − 2x = 1x = x ;
  
          -6 + 11 = 5 ; 
_____________________________
To get:  x + 5 ; 

So we have:
______________________________
 x + 5 = x + 5 ; 
______________________________

So, x = all real numbers.

x = <span>ℝ </span>
4 0
3 years ago
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