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Liono4ka [1.6K]
3 years ago
13

I need help with this question​

Mathematics
1 answer:
grigory [225]3 years ago
5 0

Answer:

A

Im too lazy to explain it it

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To play at bingo night there’s a $10 cover charge +2 dollar per bingo card. Write an equation for the cost (y) based on the numb
jasenka [17]

Answer:

y  = 2x+10

Step-by-step explanation:

y is the cost (which we don't know)

2x is the $2 per card with x representing the number of cards (which we don't know)

And of course 10 is the cover charge.

4 0
3 years ago
Number 8 pls giving brainlyist
Gekata [30.6K]

Answer:

the option number 4

Step-by-step explanation:

Hi love,

so the first step is to subtract

4/3x+7=-5

4/3x=-5-7

4/3x=-12

6 0
3 years ago
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The point (8,1) is on the line. (Remember the line continues in both directions forever.)
Scorpion4ik [409]

the answear us true im preety sure

6 0
3 years ago
PLEASE ANSWER FAST What is the average of the following two numbers? 5.67 x 10^-21 and 7.24 x 10^-19
adell [148]

Answer: The average of two numbers is 3.64835\times 10^{-19}.

Explanation:

The first term is,

5.67\times10^{-21}

The second term is,

7.24\times10^{-19}

Average formula is,

Average=\frac{\text{Sum of observations}}{\text{Number of observations}}

Average=\frac{5.67\times10^{-21}+7.24\times10^{-19}}{2}

Average=\frac{5.67\times 10^{-2}\times10^{-19}+7.24\times10^{-19}}{2}

Average=\frac{0.0567\times10^{-19}+7.24\times10^{-19}}{2}

Average=\frac{(0.0567+7.24)\times10^{-19}}{2}

Average=\frac{(7.2967)\times10^{-19}}{2}

Average=3.64835\times10^{-19}

Therefore, the average of two numbers is 3.64835\times 10^{-19}.

4 0
3 years ago
How much will be in an account at the end of 2 years if 12,000 is invested at 5% compounded annually
MatroZZZ [7]
That would be 
12,000(1.05)^2 =   13,230
3 0
3 years ago
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