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vredina [299]
2 years ago
7

Use the distributive property to rewrite this expression. 4(y + 6)

Mathematics
2 answers:
inn [45]2 years ago
8 0

Answer:

4y + 24

Step-by-step explanation:

4(y + 6)
(4 * y) + (4 * 6)
(4y) + (24)
4y + 24

Stolb23 [73]2 years ago
6 0

Answer:

4y+24, when we multiply 4(y+6) using the distributive property we get 4y+24

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X=2/7*(13)
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What is 4²(4²)? <br> 2. 5⁴(5)÷2¹? <br> 3. (5+3)²? <br> Solve the following expressions
Nat2105 [25]

Answer:

256, 3125/2, 64

Step-by-step explanation:

4^2(4^2)=16(16)=256

5^4(5)/2^1=625(5)/2=3125/2

(5+3)^2=8^2=8*8=64

7 0
3 years ago
Joan was asked to draw a right triangle how many right angles are in a right triangle?
Paha777 [63]
One angle is inside a right triangle
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Read 2 more answers
i need help asap please dont type random anwsers, that will result in it being deleted. GIVING BRAINLIEST ONLY TO CORRECT, INCOR
Veseljchak [2.6K]

Answer:

The area of the rectangle <em>TOUR</em> is 80.00 unit².

Step-by-step explanation:

The area of a rectangle is computed using the formula:

Area\ of\ a\ Rectangle=length\times width

Since the dimensions of the rectangle are not provided we can compute the dimensions using the distance formula for two points.

The distance formula using the two point is:

distance=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

Considering the rectangle <em>TOUR</em> the area formula will be:

Area of Rectangle <em>TOUR</em> = <em>TO × OU</em>

The co-ordinates of the four vertices of a triangle are:

T = (-8, 0), O = (4, 4), U = (6, -2) and R = (-6, -6)

Compute the distance between the vertices <em>T</em> and <em>O</em> as:

TO=\sqrt{(4-(-8))^{2}+(4-0)^{2}}\\=\sqrt{12^{2}+4^{2}} \\=\sqrt{160} \\=4\sqrt{10}

Compute the distance between the vertices <em>O </em>and <em>U</em> as:

OU=\sqrt{(6-4)^{2}+(-2-4)^{2}}\\=\sqrt{2^{2}+6^{2}} \\=\sqrt{40} \\=2\sqrt{10}

Compute the area of rectangle TOUR as follows:

Area\ of\ TOUR=TO\times OU\\=4\sqrt{10}\times 2\sqrt{10}\\=80\\\approx80.00 unit^{2}

Thus, the area of the rectangle <em>TOUR</em> is 80.00 unit².

6 0
3 years ago
What quadratic equation could be solved to find any solutions to the system of equations?
Kipish [7]

Answer:

Step-by-step explanation:

x²+7x-11=-5x+6

x²+7x+5x-11-6=0

x²+12x-17=0

x=\frac{-12\pm \sqrt{12^2-4*1*(-17)} }{2*1} \\=\frac{-12 \pm \sqrt{144+68} }{2} \\=\frac{-12 \pm \sqrt{212}}{2} \\=\frac{-12+2\sqrt{53}}{2}\\=-6 \pm \sqrt{53}

7 0
3 years ago
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