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3 years ago

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Which is the graph of 3x – 2y = 6? A coordinate plane with a line passing through (negative 2, 0) and (0, 3). A coordinate plane

with a line passing through (0, negative 3) and (2, 0). A coordinate plane with a line passing through (0, negative 2) and (3, 0). A coordinate plane with a line passing through (negative 3, 0) and (0, 2).

2 answers:

Rainbow [258]3 years ago

5 0

Answer:

The answer to your question is A coordinate plane with a line passing through (0, -3) and (2,0)

Step-by-step explanation:

Line

3x - 2y = 6

Solve for y

-2y = -3x + 6

y = 3/2 x - 3

Find "y" when x = 0

y = 3/2(0) - 3

y = -3 Point (0, -3)

Find "x" when y = 0

0 = 3/2x - 3

3 = 3/2 x

x = 6/3

x = 2 Point (2, 0)

Vedmedyk [2.9K]3 years ago

3 0

Answer:

B/ the 2nd graph

Step-by-step explanation:

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Trava [24]

Answer:

(a) $\log_3(\dfrac{81}{3})=3$

(b) $\log_5(\dfrac{625}{25})=2$

(c) $\log_2(\dfrac{64}{8})=3$

(d) $\log_4(\dfrac{64}{16})=1$

(e) $\log_6(36^4)=8$

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Step-by-step explanation:

Let as consider the given equations are $\log_3(\dfrac{81}{3})=?,\log_5(\dfrac{625}{25})=?,\log_2(\dfrac{64}{8})=?,\log_4(\dfrac{64}{16})=?,\log_6(36^4)=?,\log(100^3)=?$ .

(a)

$\log_3(\dfrac{81}{3})=\log_3(27)$

$\log_3(\dfrac{81}{3})=\log_3(3^3)$

$\log_3(\dfrac{81}{3})=3$ $[\because \log_aa^x=x]$

(b)

$\log_5(\dfrac{625}{25})=\log_5(25)$

$\log_5(\dfrac{625}{25})=\log_5(5^2)$

$\log_5(\dfrac{625}{25})=2$ $[\because \log_aa^x=x]$

(c)

$\log_2(\dfrac{64}{8})=\log_2(8)$

$\log_2(\dfrac{64}{8})=\log_2(2^3)$

$\log_2(\dfrac{64}{8})=3$ $[\because \log_aa^x=x]$

(d)

$\log_4(\dfrac{64}{16})=\log_4(4)$

$\log_4(\dfrac{64}{16})=1$ $[\because \log_aa^x=x]$

(e)

$\log_6(36^4)=\log_6((6^2)^4)$

$\log_6(36^4)=\log_6(6^8)$

$\log_6(36^4)=8$ $[\because \log_aa^x=x]$

(f)

$\log(100^3)=\log((10^2)^3)$

$\log(100^3)=\log(10^6)$

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Step-by-step explanation:

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Step-by-step explanation:

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