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3 years ago

HELP ASAP PLZ IM TIMED

Mathematics

2 answers:

Darya [45]3 years ago

7 0

Total area of the board = 9 x 7 = 63 square cm.

Area of shaded part = 3 x 7 = 21 square cm.

Probability of landing in shaded area = 21/63 = 1/3 = 0.33 x 100 = 33%

olga nikolaevna [1]3 years ago

6 0

Answer:

HELP ASAP PLZ IM TIMED

Suppose a dart is thrown at the dartboard shown below, and it is equally likely that the dart will land anywhere on the board. Find the probability that it lands on the shaded region. Round to the nearest

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A=(2 3) (-1 4) Calculate A^2-6A+11I

disa [49]

Answer:

A² - 6A + 11 I = $\left[\begin{array}{ccc}0&0\\0&0\end{array}\right]$

Step-by-step explanation:

Given the matrix

$A=\left[\begin{array}{ccc}2&3\\-1&4\end{array}\right]$

Calculate A² - 6A + 11 I

$A^2 = A*A= \left[\begin{array}{ccc}2&3\\-1&4\end{array}\right] *\left[\begin{array}{ccc}2&3\\-1&4\end{array}\right] = \left[\begin{array}{ccc}2*2-3*1&2*3+3*4\\-1*2-4*1&-1*3+4*4\end{array}\right] =\left[\begin{array}{ccc}1&18\\-6&13\end{array}\right]$

$6A=6*\left[\begin{array}{ccc}2&3\\-1&4\end{array}\right] =\left[\begin{array}{ccc}12&18\\-6&24\end{array}\right]$

$11 I = 11 * \left[\begin{array}{ccc}1&0\\0&1\end{array}\right] =\left[\begin{array}{ccc}11&0\\0&11\end{array}\right]$

∴ A² - 6A + 11 I = $\left[\begin{array}{ccc}1&18\\-6&13\end{array}\right] -\left[\begin{array}{ccc}12&18\\-6&24\end{array}\right] +\left[\begin{array}{ccc}11&0\\0&11\end{array}\right] =\left[\begin{array}{ccc}0&0\\0&0\end{array}\right]$

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Shkiper50 [21]

I velieve u multiply the 3s to cancel eachother out

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Mnenie [13.5K]

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