1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Doss [256]
2 years ago
6

Please help UwU ....................................

Mathematics
2 answers:
hram777 [196]2 years ago
6 0

Answer:

1. (3)  2. (4) 3. (-1)

Step-by-step explanation:

if you graph them then you get the answer.

gavmur [86]2 years ago
6 0

Answer:

Point A is (-2, 3)
Point B is (2, 4)

Point C is (0, -1)

Step-by-step explanation:

I did this a long time ago. Good luck :)

You might be interested in
BEST ANSWER GETS BRAINLIEST!!! PLEASE HELP
Ksenya-84 [330]
The answer is 3X + 12 because in he distributive property you must multiply both the 3X and the 4 by 3

3x1=3 hence the 3X

and 3x4 = 12 <span />
8 0
3 years ago
Four cards are dealt from a standard fifty-two-card poker deck. What is the probability that all four are aces given that at lea
elena-s [515]

Answer:

The probability is 0.0052

Step-by-step explanation:

Let's call A the event that the four cards are aces, B the event that at least three are aces. So, the probability P(A/B) that all four are aces given that at least three are aces is calculated as:

P(A/B) =  P(A∩B)/P(B)

The probability P(B) that at least three are aces is the sum of the following probabilities:

  • The four card are aces: This is one hand from the 270,725 differents sets of four cards, so the probability is 1/270,725
  • There are exactly 3 aces: we need to calculated how many hands have exactly 3 aces, so we are going to calculate de number of combinations or ways in which we can select k elements from a group of n elements. This can be calculated as:

nCk=\frac{n!}{k!(n-k)!}

So, the number of ways to select exactly 3 aces is:

4C3*48C1=\frac{4!}{3!(4-3)!}*\frac{48!}{1!(48-1)!}=192

Because we are going to select 3 aces from the 4 in the poker deck and we are going to select 1 card from the 48 that aren't aces. So the probability in this case is 192/270,725

Then, the probability P(B) that at least three are aces is:

P(B)=\frac{1}{270,725} +\frac{192}{270,725} =\frac{193}{270,725}

On the other hand the probability P(A∩B) that the four cards are aces and at least three are aces is equal to the probability that the four card are aces, so:

P(A∩B) = 1/270,725

Finally, the probability P(A/B) that all four are aces given that at least three are aces is:

P=\frac{1/270,725}{193/270,725} =\frac{1}{193}=0.0052

5 0
3 years ago
(pleas help) Which statement describes the following expression? 6 x (3,117 + 724)
miskamm [114]

Answer:

6 times the value of 3,117 plus 724

Step-by-step explanation:

Hope that helps :)

3 0
3 years ago
Read 2 more answers
Please help: what is 2+4+4+10? I will five brainliest
telo118 [61]

Answer:

It is 20

Step-by-step explanation:

Use your fingers if necessary

5 0
3 years ago
Which statements are true about these lines? Check all that apply. Line RS has a slope of 6. Line SW has an undefined slope. Lin
brilliants [131]
Line SW is perpendicular to line RS, but not to line TV
3 0
3 years ago
Read 2 more answers
Other questions:
  • Which answer is the slope of of the line with equation 5x+y=15
    10·1 answer
  • The expression 9x ^(2)-5x -7 has___ terms and a constant of ____ .
    9·1 answer
  • Will give brainliest
    15·2 answers
  • 1/2 divided by 2/5 using a model
    13·1 answer
  • Suppose the population of a town is 8,600 and is growing 3%every year. Predict the popularion after 3 years
    9·2 answers
  • Need help ASAP plzzzzzzzzzz
    10·2 answers
  • Simplify the expression as a single fraction<br><br> 2a/3 + a/4
    11·1 answer
  • 673 divided by 458 please HELPPP!!!!
    15·1 answer
  • What table shows a proportional relationship?
    7·1 answer
  • Plz help with this asap
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!