3 years ago

In the diagram below,

Mathematics

1 answer:

sergey [27]3 years ago

5 0

Can you attach a picture because this is very hard to read

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Based on past experience, a telemarketing firm has found that calls to prospective customers take an average of 2.0 minutes, wit

xenn [34]

Answer: Our required probability would be 0.9641.

Step-by-step explanation:

Since we have given that

Number of hours he works a day = 8

So, Number of minutes he worked in a day = $8\times 60=480\ minutes$

Number of calls = 220

So, Average $=\bar{x}=\dfrac{480}{220}=2.18\ minutes$

Standard deviation $=s=\dfrac{\sigma}{\sqrt{n}}=\dfrac{1.5}{\sqrt{220}}=0.10$

Mean = μ = 2.0 minutes

Standard deviation = σ = 1.5 minutes

Using the normal distribution, we get that

$z=\dfrac{\bar{x}-\mu}{s}\\\\z=\dfrac{2.18-2.0}{0.10}\\\\z=1.8$

So, the probability that Albert will meet or exceed his quota would be

$P(X\leq 2.18)=P(z\leq 1.8)=0.9641$

Hence, our required probability would be 0.9641.

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3 years ago

How many decimal places are in the product? 0. 053×2. 78.

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Answer:

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Step-by-step explanation:

you must solve the math

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Find the greatest common factor 32a^3b^2, 44ab^3 and 40a^2b

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$\32a^3b^2 \ , \ 44ab^3 \ , \ 40a^2b\\
$

$\text {Taking out common factor : } \\ \\
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3 years ago