5/13
The x value is negative (second quadrant). 13 is the hypotenuse. So the missing side is 13^2 = (-12)^2 + y^2.
Sin theta is the opposite (5) over hypotenuse (13).
Answer:
(2, 5).
Step-by-step explanation:
The length of the line joining the first 2 points = (5 - 3) = 2 units. This is a vertical line because the 2 x coordinates ( -6 and - 6) are equal.
The line joining ( -6 , 3) and (2 , 3) is horizontal and is 2 - -6 = 8 units long.
Because we have a rectangle the point we need to find must have x coordinate of 2 and the y coordinate will be 2 more than the y coordinate 3.
.So it is (2, 5),
You must have been taught postulates and theorems that allow you to prove triangles congruent, such as SSS, SAS, ASA, etc. Look at the given information of a proof, and see how from the given information, using definitions, postulates, and theorems you have already learned, you can show pairs of corresponding sides and angles to be congruent that will fit into the above methods. Then use one of the methods to prove the triangles congruent.
<span>The maxima of a differential equation can be obtained by
getting the 1st derivate dx/dy and equating it to 0.</span>
<span>Given the equation h = - 2 t^2 + 12 t , taking the 1st derivative
result in:</span>
dh = - 4 t dt + 12 dt
<span>dh / dt = 0 = - 4 t + 12 calculating
for t:</span>
t = -12 / - 4
t = 3
s
Therefore the maximum height obtained is calculated by
plugging in the value of t in the given equation.
h = -2 (3)^2 + 12 (3)
h =
18 m
This problem can also be solved graphically by plotting t
(x-axis) against h (y-axis). Then assigning values to t and calculate for h and
plot it in the graph to see the point in which the peak is obtained. Therefore
the answer to this is:
<span>The ball reaches a maximum height of 18
meters. The maximum of h(t) can be found both graphically or algebraically, and
lies at (3,18). The x-coordinate, 3, is the time in seconds it takes the ball
to reach maximum height, and the y-coordinate, 18, is the max height in meters.</span>
Answer:
The midpoint of the given coordinates is 
.
Step-by-step explanation:
We have given two coordinates (3,15) and (20,8).
Let we have given a line segment PQ whose P coordinate is (3,15) and Q coordinate is (20,8).
We have to find out the mid point M(x,y) of the line segment PQ.
Solution,
By the mid point formula of coordinates, which is;
On substituting the given values, we get;
We can also say that 
Hence The midpoint of the given coordinates is .
