I'm pretty sure that the answer to your question would be 27. hope that helps.
I think the answer is 180
Answer:
Supongo que tenemos dos ángulos A y B
"la mitad de A mas la tercera parte de B es igual a 15°" (también supongo que son grados)
A/2 + B/3 = 15°
A/2 = 15° - (B/3)
A = 30° - 2*(B/3)
Ahora queremos calcular:
2*sin(3*A)/cos(2*B)
pero podemos reemplazar A por lo que tenemos arriba:
2*sin(3*(30° - 2*(B/3)))/cos(2*B)
2*sin(90° - 2*B)/cos(2*B)
y como sabemos,
Sin( 90° - x) = Sin(90°)*cos(-x) + cos(90°)*sin(-x) = cos(-x) = cos(x)
entonces:
2*sin(90° - 2*B)/cos(2*B) = 2*cos(2*B)/cos(2*B) = 2*1 = 2.
The answer is 7(x+5) ive had the exact question before!! Hope i helped u!!!!
The answer to this question is 0.05
