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2 years ago

State if the two triangles are congruent if they are state how you know

Mathematics

1 answer:

kykrilka [37]2 years ago

4 0

Answer:

You will now because the sides are equal. All sides must be equal to be congruent.

Step-by-step explanation:

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Arrange the steps in the correct order to express cos3x in terms of cosx cos(2x)cos(x)-sin(2x)(x) [1-sin^2(x)]cos(x)-[2sin(x)cos

noname [10]

cos(3x) = cos(2x+x)

= cos(2x) cos (x) -sin(2x)sin(x)

$=(1-2sin^2(x)) cos(x)-(2 sin(x) cos(x)) sin(x)$

$= cos x -2sin^2(x) cos(x) -2sin^2(x) cos(x)$

$= cos(x) - 4 sin^2(x) cos(x)$

$cos(x)(1-4sin^2(x))$

$=cos(x(1-4(1-cos^2(x))$

$=cos(x)(1-4+4cos^2(x))$

$= cos(x)-4cos(x)+4cos^3(x)$

$=-3cos(x)+4cos^3(x)$

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3 years ago

Will give BRAINLIEST!!!!

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Answer:

your day going so far so good 1

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3 years ago

Read 2 more answers

If cheese is $4.40 per kg, what should I pay for 200 g?

Dvinal [7]

1kg = 1000g
1000g/5g= 200g
4.40/5 = 0.88

3 0

3 years ago

Drag the tiles to the correct boxes to complete the pairs not all tiles will be used match each quadratic graph to its respectiv

ch4aika [34]

Answer:

Part 1) The function of the First graph is $f(x)=(x-3)(x+1)$

Part 2) The function of the Second graph is $f(x)=-2(x-1)(x+3)$

Part 3) The function of the Third graph is $f(x)=0.5(x-6)(x+2)$

See the attached figure

Step-by-step explanation:

we know that

The quadratic equation in factored form is equal to

$f(x)=a(x-c)(x-d)$

where

a is the leading coefficient

c and d are the roots or zeros of the function

Part 1) First graph

we know that

The solutions or zeros of the first graph are

x=-1 and x=3

The parabola open up, so the leading coefficient a is positive

The function is equal to

$f(x)=a(x-3)(x+1)$

Find the value of the coefficient a

The vertex is equal to the point (1,-4)

substitute and solve for a

$-4=a(1-3)(1+1)$

$-4=a(-2)(2)$

$a=1$

therefore

The function is equal to

$f(x)=(x-3)(x+1)$

Part 2) Second graph

we know that

The solutions or zeros of the first graph are

x=-3 and x=1

The parabola open down, so the leading coefficient a is negative

The function is equal to

$f(x)=a(x-1)(x+3)$

Find the value of the coefficient a

The vertex is equal to the point (-1,8)

substitute and solve for a

$8=a(-1-1)(-1+3)$

$8=a(-2)(2)$

$a=-2$

therefore

The function is equal to

$f(x)=-2(x-1)(x+3)$

Part 3) Third graph

we know that

The solutions or zeros of the first graph are

x=-2 and x=6

The parabola open up, so the leading coefficient a is positive

The function is equal to

$f(x)=a(x-6)(x+2)$

Find the value of the coefficient a

The vertex is equal to the point (2,-8)

substitute and solve for a

$-8=a(2-6)(2+2)$

$-8=a(-4)(4)$

$a=0.5$

therefore

The function is equal to

$f(x)=0.5(x-6)(x+2)$

3 0

3 years ago

Elijah earns $200 for 8 hours of work.What is the rate (in dollars per item)

MAXImum [283]

25 dollars per hour should be the correct answer

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3 years ago