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Minchanka [31]
3 years ago
15

9.5x - 2.5 for x = 9 What is the solution

Mathematics
2 answers:
Oksana_A [137]3 years ago
7 0

Just substitue 9 for x in the expression.

= 9.5(9) - 2.5

= 85.5 - 2.5

= 83

Citrus2011 [14]3 years ago
7 0

Answer:

86

Step-by-step explanation:

The original equation is 9.5 times x - 2.5

9.5(9) - 2.5

9.5(9) = 88.5

88.5 - 2.5 = 86

9.5x - 2.5 = 86

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250 * 0.20 = $50 sale
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Naitik exercised for
kati45 [8]
<h3>Answer:  Aryan spent more time exercising.</h3>

=======================================================

Explanation:

Use your calculator to convert each fraction into decimal form

2/3 = 0.67 approximately

3/4 = 0.75 exact

The decimal 0.75 is larger than 0.67, in which we can think of it like saying "75 is larger than 67".

So 0.67 < 0.75 which leads to 2/3 < 3/4.

Aryan spent more time exercising.

--------------

We could stop there, but if you wanted to know how much longer he spent exercising, then we subtract the two fractions to get

3/4 - 2/3

9/12 - 8/12

(9-8)/12

1/12

Aryan spent 1/12 of an hour longer exercising compared to Naitik

1/12 hour = (1/12)*60 = 60/12 = 5 minutes

He spent 5 extra minutes exercising.

----------------

Notes:

  • 2/3 hours = (2/3)*60 = 40 minutes
  • 3/4 hours = (3/4)*60 = 45 minutes
  • 45-40 = 5 extra minutes of exercise
5 0
3 years ago
X^3 = ? Please write the answer correctly.
photoshop1234 [79]

Answer: (x)(x)(x) = x^3.

Step-by-step explanation:

x^3 means multiply x by it's self 3 times.

Hope this helps..

4 0
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In a class of 31 pupils, 19 like apples, 15 like oranges and 4
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F(x) = e^-x . Find the equation of the tangent to f(x) at x=-1​
natima [27]

Answer:

The <em>equation</em> of the tangent line is given by the following equation:

\displaystyle y - \frac{1}{e} = \frac{-1}{e} \bigg( x - 1 \bigg)

General Formulas and Concepts:

<u>Algebra I</u>

Point-Slope Form: y - y₁ = m(x - x₁)

  • x₁ - x coordinate
  • y₁ - y coordinate
  • m - slope

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Multiplied Constant]:
\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)

Derivative Rule [Basic Power Rule]:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:
\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Step-by-step explanation:

*Note:

Recall that the definition of the derivative is the <em>slope of the tangent line</em>.

<u>Step 1: Define</u>

<em>Identify given.</em>

<em />\displaystylef(x) = e^{-x} \\x = -1

<u>Step 2: Differentiate</u>

  1. [Function] Apply Exponential Differentiation [Derivative Rule - Chain Rule]:
    \displaystyle f'(x) = e^{-x}(-x)'
  2. [Derivative] Rewrite [Derivative Rule - Multiplied Constant]:
    \displaystyle f'(x) = -e^{-x}(x)'
  3. [Derivative] Apply Derivative Rule [Derivative Rule - Basic Power Rule]:
    \displaystyle f'(x) = -e^{-x}

<u>Step 3: Find Tangent Slope</u>

  1. [Derivative] Substitute in <em>x</em> = 1:
    \displaystyle f'(1) = -e^{-1}
  2. Rewrite:
    \displaystyle f'(1) = \frac{-1}{e}

∴ the slope of the tangent line is equal to  \displaystyle \frac{-1}{e}.

<u>Step 4: Find Equation</u>

  1. [Function] Substitute in <em>x</em> = 1:
    \displaystyle f(1) = e^{-1}
  2. Rewrite:
    \displaystyle f(1) = \frac{1}{e}

∴ our point is equal to  \displaystyle \bigg( 1, \frac{1}{e} \bigg).

Substituting in our variables we found into the point-slope form general equation, we get our final answer of:

\displaystyle \boxed{ y - \frac{1}{e} = \frac{-1}{e} \bigg( x - 1 \bigg) }

∴ we have our final answer.

---

Learn more about derivatives: brainly.com/question/27163229

Learn more about calculus: brainly.com/question/23558817

---

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

3 0
2 years ago
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