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Verizon [17]
2 years ago
10

What’s the answer for this? 5 > -3+y

Mathematics
1 answer:
IRINA_888 [86]2 years ago
4 0

Answer:

y < 5+3

y < 8

pls mark as brainlest

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Paddy and Anna each invest $2000 for 5 years.
Serga [27]

Answer: r= 1.22

Step-by-step explanation:

Formula for amount with simple interest = P(1+rt)

, where

P= principal value , r= rate of interest , t = time.

Given: P=  $2000, t= 5 years, r= 1.25% = 0.0125

A=2000(1+0.0125\times5)\\\\=2000(1.0625)=2125

Formula to compute compound amount : P(1+r)^t

=2000(1+r)^5

When both have same worth then

2000(1+r)^5=2125\\\\\\ (1+r)^5=\dfrac{2125}{2000}\\\\\\ (1+r)^5=1.0625

taking log on both sides , we get

5\ln (1+r)=\ln 1.0625\\\\\\ 5\ln (1+r)=0.0606246\\\\\\ \ln (1+r)=0.012125\\\\\\ 1+r=e^{0.005266}\\\\\\ 1+r=1.0122\\\\ r=0.0122\\\\ \\ r=1.22\%

Hence, Value of r= 1.22

6 0
3 years ago
7x + 5y - X + 2y + 3x
larisa [96]

Answer:

9x+7y

Step-by-step explanation:

please see the image that I have attached

8 0
3 years ago
Read 2 more answers
250 grams of sugar cost 150 dollars at Shop X. 100 grams of sugar cost 95 dollars at Shop Y. What is the difference in cost per
nata0808 [166]
<h2>Answer:</h2>

350 dollars

<h2>Step-by-step explanation:</h2>

<em>(step 1) Find the cost per kilogramme of sugar in shop X</em>

In shop X:

250 grams of sugar costs 150 dollars.

<em>Remember that;</em>

1000 grams = 1 kilogramme.

=> 250 grams will be equal to 0.25 kilogramme

Therefore (replacing 250 grams with 0.25 kilogramme) in shop X;

0.25 kilogramme of sugar costs 150 dollars

Now, if

0.25 kilogramme = 150 dollars,

=> 1 kilogramme =  150 dollars x 1 kilogramme / 0.25 kilogramme

=> 1 kilogramme = 600 dollars

Therefore, the cost per kilogramme of sugar in shop X is 600 dollars

<em>(step 2) Find the cost per kilogramme of sugar in shop Y</em>

In shop Y:

100 grams of sugar costs 95 dollars.

<em>Remember that;</em>

1000 grams = 1 kilogramme.

=> 100 grams will be equal to 0.1 kilogramme

Therefore (replacing 100 grams with 0.1 kilogramme) in shop Y;

0.1 kilogramme of sugar costs 95 dollars

Now, if

0.1 kilogramme = 95 dollars,

=> 1 kilogramme =  95 dollars x 1 kilogramme / 0.1 kilogramme

=> 1 kilogramme = 950 dollars

Therefore, the cost per kilogramme of sugar in shop Y is 950 dollars

<em>(step 3) Find the difference in cost per kilogramme of sugar between the two shops</em>

The difference is calculated by subtracting the cost per kilogramme of sugar in shop X from the cost per kilogramme of sugar in shop Y. i.e

=> cost per kilogramme of sugar in shop Y - cost per kilogramme of sugar in shop X

=> 950 dollars - 600 dollars

=> 350 dollars.

Therefore, the difference in cost per kilogramme is 350 dollars

3 0
3 years ago
two ferries start moving toward each other from opposite riverbanks, a and b. when they pass each other for the first time, the
Usimov [2.4K]

Let 'x' be the distance from THE far bank   where 700 is the distance to the NEAR bank

boat one has travelled 700    (rate = 700/unit time)         boat two has travelled   x    rate = x / unit time

boat one then travels   x  + 400  more      and boat two travels   700 + (700+x -400) more    when they meet

The time is the same      rate x time = distance      distance/rate = time     equate the distances divided by the respective rates

(700 + x + 400)/700     =    (  x  +  700     +  (700+x-400) )/x

1100x + x^2 = 1400x + 700000

x^2-300x -700000 = 0                         quadratic formula yields  x = 1000  

One boat travels 700   the other   1000 whe they first meet.....width of river =   700+ 1000 = 1700 m

3 0
3 years ago
Consider triangle ABC. The legs have a length of 5 units each. What is the length of the hypotenuse of the triangle?
Korvikt [17]

Answer:

5\sqrt{2} units.

Step-by-step explanation:

We have been given that two legs of triangle ABC measures 5 units each. We are asked to find the length of the hypotenuse.

We will use Pythagoras theorem to solve for the hypotenuse of triangle ABC.

\text{Hypotenuse}^2=\text{Leg}^2+\text{Leg}^2

Substituting our given values in above equation we will get,

\text{Hypotenuse}^2=5^2+5^2

\text{Hypotenuse}^2=25+25

\text{Hypotenuse}^2=50

Upon taking square root of both sides of our equation we will get,

\text{Hypotenuse}=\sqrt{50}

\text{Hypotenuse}=\sqrt{25*2}

\text{Hypotenuse}=5\sqrt{2}

Therefore, the length of hypotenuse of triangle ABC is 5\sqrt{2} units.

6 0
3 years ago
Read 2 more answers
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