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makvit [3.9K]
2 years ago
13

Martin will earn $20 per hour at a new job. During training he will earn $15 per hour. What percent of Martin’s regular hourly r

ate well he earned during training?
Mathematics
1 answer:
Contact [7]2 years ago
4 0

Answer:

75%

Step-by-step explanation:

To find the percentage, you would divide the training hourly rate by Martin's regular hourly rate and multiply the quotient by 100

If martin normally earns $20 and he earns $15 during training, that means you would divide 15 by 20.

15/20=.75 and .75x100=75, so Martin earns 75% of his regular hourly rate during training

Please mark as brainliest ;)

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yanalaym [24]
I think you add the exponents im not sure haven't done it in long time
4 0
4 years ago
Use the arc length formula and the given information to find r.. s = 16 cm, θ = 48°; r = ?
saveliy_v [14]

Answer:

The value for r is 19.1 cm

Step-by-step explanation:

We have been given that  s = 16 cm, θ = 48° and we have to find the radius r.

We know the relation

\theta=\frac{s}{r}\\\\r=\frac{s}{\theta},\text{ where }\theta \text{ is in radian}

Hence, first of all convert the angle in radian

θ = 48°= 0.837758 radian

Therefore, we have

r=\frac{16}{0.837758}\\\\r=19.1\text{ cm}



8 0
3 years ago
Read 2 more answers
Which shape has 1 vertex
SpyIntel [72]
It could be the cone.
3 0
3 years ago
Read 2 more answers
I NEED HELP !!! 30 points!!!! and brainliest :)<br><br>please give sensible answer :(<br><br><br>​
Allushta [10]

Answer:

Step-by-step explanation:

9) PQR Is an isosceles triangle

=> ∠PRQ = (180° - x)/2

PRS is an isosceles right triangle

=> ∠PRS = 45°

Have: ∠PRS + ∠PRQ = 115°

=> \frac{180-x}{2}+45=115 \\

=> 180 - x = (115 - 45).2 = 140

<=> x = 180 - 140 = 40

10) ABD is an isosceles right triangle => ∠ABD = 45°

BCD is an equilateral triangle => ∠CBD = 60°

have: x = ∠ABD + ∠CBD = 45° + 60° = 105°

11) have: x = y (2)

PQT is an isosceles triangle => ∠PQT = 180 - 70.2 = 40

QTS   is an isosceles triangle => ∠TQS = 180 -2x

QRS   is an isosceles triangle => ∠RSQ = y

have: 40 + 180 - 2x + y = 180 => 2x - y = 40 (1)

(1)(2) => \left \{ {{y=x} \atop {2x-y=40}} \right.\\\\=> \left \{ {{x=40} \atop {y=40}} \right.

=> x + y = 80

12) EFJ Is an equilateral  triangle => ∠FJE = 60

∠FJE is the outer angle of the triangle FHJ but FHJ is an isosceles triangle

=> 60 = 2.∠JHF => ∠JHF = 30°

∠JHF is the outer angle of the triangle FHG

=> 30° = 2x

<=> x = 15°

7 0
3 years ago
Plz help me their is a picture
11111nata11111 [884]

Answer:

simple. y=x+2

Step-by-step explanation:

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