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jenyasd209 [6]
2 years ago
11

A washer and a dryer cost 984 combined. The washer costs 84 more than the dryer. What is the cost of the dryer?

Mathematics
2 answers:
kaheart [24]2 years ago
6 0

Answer:

$375

Step-by-step explanation:

hope this helps! :)

Mariulka [41]2 years ago
3 0

Answer:

$450

Not exactly sure how to explain it, but here's my process.

984 - 84 = 900

Cause the washer costs $84 more.

900 / 2 = 450

Cause there are 2 things within the purchase.

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Put into scientific notation 2910000
dolphi86 [110]

Answer:

The Answer is: 2.91 x 10^6

Step-by-step explanation:

Move the decimal from the right to left and count the number of moves, stopping at the next to last number.

Given:

2,910,000

In Scientific notation:

2.91 x 10^6

Hope this helps! Have an Awesome Day!! :-)

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Which triangle is a translation of triangle P? On a coordinate plane, triangle P is shifted 5 units to the right and 7 units up
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Answer:

Triangle C

Step-by-step explanation:

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Answer:

Step-by-step explanation:

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How do you turn .15 repeating into a fraction show work
mafiozo [28]

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2 years ago
In the illustration below, the three cube-shaped tanks are identical. The spheres in any given tank
fredd [130]

Answer:

1) Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) Amount \ of \, water \ remaining \ in \, the \ tank \ is \  \frac{x^3(6-\pi) }{6}

Step-by-step explanation:

1) Here we have;

First tank A

Volume of tank = x³

The  volume of the sphere = \frac{4}{3} \pi r^3

However, the diameter of the sphere = x therefore;

r = x/2 and the volume of the sphere is thus;

volume of the sphere = \frac{4}{3} \pi \frac{x^3}{8}= \frac{1}{6} \pi x^3

For tank B

Volume of tank = x³

The  volume of the spheres = 8 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 2·D = x therefore;

r = x/4 and the volume of the sphere is thus;

volume of the spheres = 8 \times \frac{4}{3} \pi (\frac{x}{4})^3= \frac{x^3 \times \pi }{6}

For tank C

Volume of tank = x³

The  volume of the spheres = 64 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 4·D = x therefore;

r = x/8 and the volume of the sphere is thus;

volume of the spheres = 64 \times \frac{4}{3} \pi (\frac{x}{8})^3= \frac{x^3 \times \pi }{6}

Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) For the 4th tank, we have;

number of spheres on side of the tank, n is given thus;

n³ = 512

∴ n = ∛512 = 8

Hence we have;

Volume of tank = x³

The  volume of the spheres = 512 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 8·D = x therefore;

r = x/16 and the volume of the sphere is thus;

volume of the spheres = 512\times \frac{4}{3} \pi (\frac{x}{16})^3= \frac{x^3 \times \pi }{6}

Amount of water remaining in the tank is given by the following expression;

Amount of water remaining in the tank = Volume of tank - volume of spheres

Amount of water remaining in the tank = x^3 - \frac{x^3 \times \pi }{6} = \frac{x^3(6-\pi) }{6}

Amount \ of \ water \, remaining \, in \, the \ tank =  \frac{x^3(6-\pi) }{6}.

5 0
3 years ago
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