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Step2247 [10]
3 years ago
14

1.)Each sandwich costs $.02 per cubic inch to make. What is the cost of each sandwich?

Mathematics
1 answer:
kirza4 [7]3 years ago
7 0
Part 1) <span>Each sandwich costs $.02 per cubic inch to make. What is the cost of each sandwich?

</span>volume for cube sandwich is 125 in³
volume for pyramid sandwich is 41.67 in³

cost of each cube sandwich=0.02*125-----> $2.5

cost of each  pyramid sandwich=0.02*41.67-----> $0.83

the answers Part 1) are
a) cost of each cube sandwich is $2.5
b) cost of each pyramid sandwich is $0.83

Part 2) <span>If each sandwich sells for $4.00 and Mr. Sammie sells 100 Cube sandwiches and 100 Pyramid Sandwiches, how much profit would Mr. Sammie make?
</span>
we know that
Profit=Sells-Costs

step 1
 find the sells
Sells=200*$4-----> $800

step 2
find the costs
Costs=100*$2.5+100*$0.83----> $333

step 3
find the profit
Profit=Sells-Costs
Profit=$800-$333-----> $467

the answer Part 2) is
the profit is $467
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In order to be differentiable everywhere, f must first be continuous everywhere, which means the limits from either side as x\to2 must be the same and equal to f(2). By definition, f(2)=2^2=4, and

\displaystyle\lim_{x\to2^-}f(x)=\lim_{x\to2}x^2=4

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so we need to have 4m+b=4.

For f to be differentiable at x=2, the derivative needs to be continuous at x=2, i.e.

\displaystyle\lim_{x\to2^-}f'(x)=\lim_{x\to2^+}f'(x)

We then need to have

\displaystyle\lim_{x\to2}2x=\lim_{x\to2}m\implies\boxed{m=4}

Then

2m+b=4\implies\boxed{b=-4}

7 0
3 years ago
Which is the correct formula to find the distance between two points (p,q) and (m,n)?
Dafna1 [17]

Answer:

The answer is d = √[(p - m)² + (q - n)²] ⇒ first answer

Step-by-step explanation:

* The distance between any to points (x1 , y1) , (x2 , y2) is

- d = √[square the difference of x- coordinates plus

        square the difference of y-coordinates]

∴ d = √[(x2 - x1)² + (y2 - y1)²] or

∴ d² = (x2 - x1)² + (y2 - y1)²

* x2 - x1 is the horizontal distance (h) and y2 - y1

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- By using Pythagoras theorem

∴ d = √[h² + v²]

∵ The two points are (p , q) and (m , n)

- Put x1 = m and y1 = n

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∴ d² = (p - m)² + (q - n)²

∴ d = √[(p - m)² + (q - n)²]

∴ The answer is d = √[(p - m)² + (q - n)²] ⇒ first answer

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3 years ago
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so fine area you do side x side and divide by two

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Yes, you'd be able to play.
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So you've attended more than 85% of the practices.
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