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olga55 [171]
2 years ago
7

In cellular respiration, glucose __________ electrons, whereas __________ electrons.

Biology
1 answer:
stiks02 [169]2 years ago
7 0

Answer:

During cellular respiration, glucose loses electrons wheras oxygen gains electrons.

Explanation:

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The primary function of the respiratory system is to provide ____________ needed by cells to metabolize nutrient molecules, and
Paraphin [41]

Answer:

Oxygen; cabondioxide,Cellular respiration

Explanation:

Breathing a Mechanism of respiration supplys Oxygen molecules which diffuses in through the respiratory tracts to reach the alveolar sacs for diffusion to the blood enroute the body cells.

These Oxygen molecules are use for combustion of metabolites e. g glucose.The reactions take place in the Matix of Mitochondrial via Citric Acid Cycle.where ATPs were produced.Molecules of Carbondioxide were librated, as byproducts.

Co factors NAD+and FAD+ trapped H+ atoms and take these accros the intramembranes . The protons were moved down their concentration gradients to supply more ATPs.The energy for the proton pump was supplied by electron chains transport system. The electrons were supplied by the splitting of Hydrogen atom carried by the co-factors to:protons and electrons.

This redox process of ATPs production is called Oxidative phosphorylation.

5 0
4 years ago
What role do the following codons (UGA, UAA, UAG) play in protein system
marshall27 [118]

Answer:

Signal the end of protein-coding sequences

Explanation:

The codons UGA, UAA, and UAG are known as stop codons. When the RNA is being translated to protein, and the RNAm reads those codons, it knows it has to end the protein sequence

4 0
2 years ago
The mean resting pulse rate for men is 72 beats per minute. a simple random sample of men who regularly work out at mitch's gym
tamaranim1 [39]

Claim: the mean resting pulse rate for men is less than 72 bpm.

Symbolic form would be: μ < 72

Step 1: null hypothesis  : μ > =  7 2 b p m

Step 2: alternative hypothesis:  μ <  7 2 b p m



Step 3: the test statistic is z = mean – μ / standard dev/sqrt (n) = -3/4 / 1.7639 = -1.92


Step 4: c v method: since z α = -1.645, the test static is z = -1.92 is less than the CV, we reject null hypothesis


            P Value method: area is 0.0274, since the p value is <= α, reject null hypothesis.

Step 5: the sample data support the claim that the mean resting pulse rate for men is less than 72 bpm.

5 0
3 years ago
Read 2 more answers
Identify three differences between prokaryotic and eukaryotic
icang [17]

a,b,c and d

Explanation:

Most prokaryotes have capsule but most eukaryotes lack capsule

Eukaryotes are generally larger than prokaryotes

The ribosomes of prokaryotes are smaller than that of eukaryotes

Generally, prokaryotes have pili but pili is absent in eukaryotes

6 0
3 years ago
:/ plz help ill give you brainiest follow 5star and ty.<br> Seriously.
gogolik [260]

Answer:

its the first option (a)

5 0
3 years ago
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