Answer:
False, I got it right on my test
Out of the following given choices;
A. major changes in the structure of Earth's layers
B. major changes that occur in the solar system
C. major changes that are recorded in the fossil record
D. major changes in the
<span> arr</span>angement
of the continents
The answer is C.
Changes in the environment in prehistoric times can be best exhibited by the evolutionary
changes of living organisms. This is best shown
by fossil records. Changes in geological times are characterized by a high rate of varying individuals of a species
and with high extinction rates.
Hello,
Here is your answer:
The proper answer tot his question is A "cross pollinated".
Your answer is A.
If you need anymore help feel free to ask me!
Hope this helps!
Answer:
Allopatric speciation occurs due to the geographical isolation between individuals of the same species. The geographical isolation can be due to canyon development, mountain formation, migration, etc.
The geographical isolation gives different environmental condition to the separated population of same species to live which allow these two population to evolve differently and evolve in different species.
So when two population becomes different species and not able to interbreed with each other when give opportunity then the allopatric speciation between the two populations becomes complete.
Answer:
1/4.
Explanation:
The autosomal dominant trait means that the trait is visible in homozygous dominant and in heterozygous condition. The X linked recessive trait will be pass down from mothers to their sons and daughters will show the trait in homozygous recessive condition only.
The man is achandroplastic dwarf ( Aa) with normal vision (XY ) is married with woman that has normal height (aa) with color blind (XhXh). They have a daughter who is dwarf ( Aa). The probability of being dwarf can be calculated by the cross Aa × aa. The offspring are Aa, Aa, aa, aa. Means 1/2 are the probability of being hetterozygous for achondroplastic . The vision probability is calculated by cross XY and XhXHh. The probability that female is heterozygous is 1/2.
So, the heterozygous probability for both trait is 1/2× 1/2 = 1/4.
