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1 year ago

Please help ! I’m in such a rush! I have to be done before 3pm and it’s already 2:30pm

Mathematics

1 answer:

lutik1710 [3]1 year ago

6 0

Answer:

170°

Step-by-step explanation:

By inspection of the diagram, the angle is 170°

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Please help me on this problem

Anna71 [15]

Answer:

The pairs of integer having two real solution for $ax^{2} -6x+c = 0$ are

$a = -4, c = 5$
$a = 1, c = 6$
$a = 2, c = 3$
$a = 3, c = 3$

Step-by-step explanation:

Given

$ax^{2} -6x+c = 0$

Now we will solve the equation by putting all the 6 pairs so we get the following

$-3x^{2} -6x-5 = 0$ for $a = -3 , c=-5$

$-4x^{2} -6x+5 = 0$ for $a = -4 , c=5$

$1x^{2} -6x+6 = 0$ for $a = 1 , c=6$

$2x^{2} -6x+3 = 0$ for $a = 2 , c=3$

$3x^{2} -6x+3 = 0$ for $a = 3 , c=3$

$5x^{2} -6x+4 = 0$ for $a = 5 , c=4$

The above all are Quadratic equations inn general form $ax^{2} +bx+c=0$

where we have a,b and c constant values

So for a real Solution we must have

$Disciminant , b^{2} -4\timesa\timesc \geq 0$

for $a = -3 , c=-5$ we have

$Discriminant =-24$ which is less than 0 ∴ not a real solution.

for $a = -4 , c=5$ we have

$Discriminant = 116$ which is greater than 0 ∴ a real solution.

for $a = 1 , c=6$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 2 , c=3$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 3 , c=3$ we have

$Discriminant =0$ which is equal to 0 ∴ a real solution.

for $a = 5 , c=4$ we have

$Discriminant =-44$ which is less than 0 ∴ not a real solution.

7 0

3 years ago

Margaret has 16 yards of fabric and she is making dresses for z doll write the expression for the length of fabric used for each

emmasim [6.3K]

<h3>The expression for the length of fabric used for each doll is $\frac{16}{z}\ yards$ </h3>

<em><u>Solution:</u></em>

Given that,

Margaret has 16 yards of fabric

she is making dresses for z doll

Therefore,

Total length of fabric = 16 yards

Number of dresses = z dolls

Therefore,

$\text{ length of fabric used for each doll } = \frac{ \text{ Total length of fabric }} {\text{ z dolls }}\\\\\text{ length of fabric used for each doll } = \frac{16}{z}\ yards$

Thus, the expression for the length of fabric used for each doll is $\frac{16}{z}\ yards$

7 0

3 years ago

The area of a rectangle is 70 m², and the length of the rectangle is 11 m less than three times the width. Find the dimensions o

11111nata11111 [884]

Step-by-step explanation:

the area of a rectangle is

length × width

in our case

length × width = 70 m²

length = 3×width - 11

we can use this second equation in the first and get

(3×width - 11) × width = 70

3×width² - 11×width - 70 = 0

the general solution to a quadratic equation is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

a = 3

b = -11

c = -70

x = (11 ± sqrt((-11)² - 4×3×-70))/(2×3) =

= (11 ± sqrt(121 + 840))/6 =

= (11 ± sqrt(961))/6

x1 = (11 + 31)/6 = 42/6 = 7

x2 = (11 - 31)/6 = -20/6 = -10/3

the negative solution is not applicable for a length in an object.

so, only x1 = 7 m is our solution.

the width of the rectangle is 7 m.

the length = 3×width - 11 = 3×7 - 11 = 21-11 = 10 m

7 0

2 years ago

What is the solution to the system of equations represented by these two lines?

Andrei [34K]

Answer:

(3,2)

Step-by-step explanation:

this is an intersecting lines which means it has one solution

8 0

2 years ago

3 csc^2(2x) + 2 cosec 2x = 1-cot^2(2x)

asambeis [7]

I am assuming you want to solve for x:-

Now cosec^2 2x = 1 - cot^2 2x so the equation becomes

3 cosec^2(2x) + 2 cosec 2x = cosec^2 2x

2 cosec^2 2x + 2 cosec 2x = 0

2 cosec 2x ( cosec 2x + 1) = 0

so 2 cosec 2x = 0 or cosec 2x = -1

cosec 2x = 0 or cosec 2x = -1

cosec 2x = 0 is indeterminate so we ignore the first one

cosec 2x = -1 can be written as 1 / sin 2x = -1

so sin 2x = -1

giving 2x = 270 degrees

Therefore x = 135 degrees answer

3 0

2 years ago