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2 years ago

Please help ! I’m in such a rush! I have to be done before 3pm and it’s already 2:30pm

Mathematics

1 answer:

lutik1710 [3]2 years ago

6 0

Answer:

170°

Step-by-step explanation:

By inspection of the diagram, the angle is 170°

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Toxaphene is an insecticide that has been identified as a pollutant in the Great Lakes ecosystem. To investigate the effect of t

Likurg_2 [28]

Answer:

This data suggest that there is more variability in low-dose weight gains than in control weight gains.

Step-by-step explanation:

Let $\sigma_{1}^{2}$ be the variance for the population of weight gains for rats given a low dose, and $\sigma_{2}^{2}$ the variance for the population of weight gains for control rats whose diet did not include the insecticide.

We want to test $H_{0}: \sigma_{1}^{2} = \sigma_{2}^{2}$ vs $H_{1}: \sigma_{1}^{2} > \sigma_{2}^{2}$ . We have that the sample standard deviation for $n_{2} = 22$ female control rats was $s_{2} = 28$ g and for $n_{1} = 18$ female low-dose rats was $s_{1} = 51$ g. So, we have observed the value

$F = \frac{s_{1}^{2}}{s_{2}^{2}} = \frac{(51)^{2}}{(28)^{2}} = 3.3176$ which comes from a F distribution with $n_{1} - 1 = 18 - 1 = 17$ degrees of freedom (numerator) and $n_{2} - 1 = 22 - 1 = 21$ degrees of freedom (denominator).

As we want carry out a test of hypothesis at the significance level of 0.05, we should find the 95th quantile of the F distribution with 17 and 21 degrees of freedom, this value is 2.1389. The rejection region is given by {F > 2.1389}, because the observed value is 3.3176 > 2.1389, we reject the null hypothesis. So, this data suggest that there is more variability in low-dose weight gains than in control weight gains.

8 0

3 years ago

What is this I need the answer

Archy [21]

<h3>Answer is 0</h3>

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Explanation:

Logarithms are used to solve exponential equations. Specifically if you have a variable in the exponent, then you use a log to isolate the variable.

If we set the given log expression to x, then we can rewrite it into 8^x = 1. The only value of x that works is x = 0.

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Or put another way,

8^x = 1

8^x = 8^0 ... replace the 1 with 8^0

x = 0 ... the bases are equal (to 8) so the exponents must be equal

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You can use the change of base formula to directly calculate this log

$\log_8(1) = \frac{\log(1)}{\log(8)} = \frac{0}{0.903} = 0$

8 0

3 years ago

Jacob buys a watch costing £84

IceJOKER [234]

So beacause the VAT costsnyou need to move the variable to the left then consider and then thr rate will turn to 0%

7 0

3 years ago

The weight of an elephant is 1000x the weight of a cat. if the elephant weighs 14000 pounds, how many pounds does the cat weigh?

a_sh-v [17]

Answer:

Step-by-step explanation:

1000 x 14

5 0

3 years ago

Read 2 more answers

Find the area???????

Elan Coil [88]

Area of the top triangle = 0.5 * 3 * 4 = 6

Area of the parallelogram = 4 * 4 = 16

Answer is 22 units^2

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3 years ago