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3 years ago

Don’t get this question , need some help thankssss

Mathematics

1 answer:

ss7ja [257]3 years ago

3 0

Answer:

PQ = 37 Km

Step-by-step explanation:

let PQ = x , then

PR = x + 15 and QR = 3(x + 15) = 3x + 45

sum the parts and equate to 245

x + x + 15 + 3x + 45 = 245 , that is

5x + 60 = 245 ( subtract 60 from both sides )

5x = 185 ( divide both sides by 5 )

x = 37

then

PQ = x = 37 Km

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3 years ago

*****PLEASE HELP (30 POINTS)*****

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Answer:

2. C) 21.2 yd 3. B) angle IQL 4. B) 55 degree

Step-by-step explanation:

2. The area of an equilateral triangle is given by,

A = $\frac {\sqrt{3} \times a^{2}}{4}$ ------(1) where a = length of each side.

Here, a = 7 yd

so , putting a = 7 yd in (1) , we get,

A = $\frac {\sqrt{3} \times 49}{4}$ sq. yd.

$\simeq 21.2$ sq. yd.

3. B) angle IQL

4. Let, the centre of the circle be at O,

then, ∠DOB = 105° and ∠BOC = 145° (given)

so, ∠OBD = $\frac{180^{\circ} - \angle DOB}{2}$

= $\frac{180^{\circ} - 105^{\circ}}{2}$

= 37.5° [since the sum of three angles of a triangle is 180° and OB and OD are two radii of the same circle]

and, similarly, ∠OBC = $\frac{180^{\circ} - \angle COB}{2}$

= $\frac{180^{\circ} - 145^{\circ}}{2}$

= 17.5° [since the sum of three angles of a triangle is 180° and OB and OC are two radii of the same circle]

so, ∠CBD = ∠OBD + ∠OBC

= 37.5° + 17.5°

= 55°

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3 years ago