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3 years ago

❗️help me❗️2. Marissa is playing a game using the spinner below.

Mathematics

1 answer:

julia-pushkina [17]3 years ago

5 0

<h3>Answer: Choice C</h3>

Explanation:

In this answer choice, we effectively have two columns. In the first column is simply R and B, with R over B. This represents spinning either red (R) or blue (B).

Depending on the outcome, you branch the same outcomes from that.

So if you spin R, then you'll have R and B branch off that. Same idea applies to blue as well.

Something like choice D doesn't work because we have R show up twice at the very bottom.

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write a liner function domain of 123 + 4 + 5 which cannot be used to represent the arithmetic sequence sequence 12-7 to -3 + -8

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Answer:

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Step-by-step explanation:

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4 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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Which sequences of transformations confirm the congruence of shape II and shape I?

jasenka [17]

Which sequences of transformations confirm the congruence of shape II and shape I?

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4 years ago

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Evaluate the following function for (3, -1):<br> f(x, y) = 2x – 3y + xy^2

satela [25.4K]

Answer:

f(3, -1) = 12

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Algebra I</u>

Function Notation

Step-by-step explanation:

<u>Step 1: Define</u>

f(x, y) = 2x - 3y + xy²

(3, -1) is x =3 and y = -1

<u>Step 2: Evaluate</u>

Substitute: f(3, -1) = 2(3) - 3(-1) + 3(-1)²
Exponents: f(3, -1) = 2(3) - 3(-1) + 3(1)
Multiply: f(3, -1) = 6 + 3 + 3
Add: f(3, -1) = 9 + 3
Add: f(3, -1) = 12

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3 years ago

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A professor teaches a certain section of material using a lot of examples with sports and cars to illustrate. He is concerned th

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Answer:

There is difference in the scores of males and females

Step-by-step explanation:

Given that a professor teaches a certain section of material using a lot of examples with sports and cars to illustrate. He is concerned that this may have biased his instruction to favor male students

Since simple variances are unequal, we can do t test for comparison of two means with unequal variances

$H_0 : \bar x =\bar y\\H_a : \bar x \neq \bar y$

Group Group One Group Two

Mean 84.00 78.00

SD 4.00 8.00

SEM 1.26 2.53

N 10 10

The mean of Group One minus Group Two equals 6.00

95% confidence interval of this difference: From 0.06 to 11.94

t = 2.1213

df = 18

standard error of difference = 2.828

The two-tailed P value equals 0.0480

Since p <0.05 we reject null hypothesis

There is difference in the scores of males and females

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