Given the table showing the distance Randy drove on one day of her vacation as follows:
![\begin{tabular} {|c|c|c|c|c|c|} Time (h)&1&2&3&4&5\\[1ex] Distance (mi)&55&110&165&220&275 \end{tabular}](https://tex.z-dn.net/?f=%5Cbegin%7Btabular%7D%0A%7B%7Cc%7Cc%7Cc%7Cc%7Cc%7Cc%7C%7D%0ATime%20%28h%29%261%262%263%264%265%5C%5C%5B1ex%5D%0ADistance%20%28mi%29%2655%26110%26165%26220%26275%0A%5Cend%7Btabular%7D)
The rate at which she travels is given by
If Randy has driven for one more hour at the same rate, the number of hours she must have droven is 6 hrs and the total distance is given by
distance = 55 x 6 = 330 miles.
Answer:
Point C
Step-by-step explanation:
The correct answer would be D, the median 86.5.
In this set of data most of the values are in the 80's or 90's. There is only 1 number that is outside of this range, that is the value 0. It is an outlier.
When we have an outlier, the median generally gives us the better measure of central tendency.
Answer:
The common difference is 
or 0.2
Step-by-step explanation:
Given:
Arithmetic Sequence -2, -1 4/5, -1 3/5, -1 2/5,
First term = a₁ = -2
Second term = a₂ = 
Third term = a₃ = 
Fourth term = a₄ = 
To Find:
Common Difference = d = ?
Solution:
Formula for Common Difference d ,
∴ 
The common difference is or 0.2
Answer:
112 hours and 50 mins
Step-by-step explanation:
Numbers of mins worked in a day = 7×60+30 =450 mins
Now number of mins worked in 15 days = 450×15
= 6750 mins
to convert mins into hours divide by 60
6750÷60 = 112.50
that means total number of hours worked in 15 days = 112 hours and 50 mins
