According to the data set, where should the
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The slope m of a line
through points 
and 
is given by :<span>
Thus, the slope of the line passing through points </span><span>(−1, 7) and (2, 10) is
</span>
<span>
The equation of a line with slope m passing through a point P(a, b) is given by
(y-b)=m(x-a).
We can consider any of the points (-1, 7), or (2, 10). Let's choose (2, 10):
y-10=1(x-2)
y-10=x-2
y-x=-2+10
y-x=8
Answer: </span><span>C. −x+y=8</span>
Thus, the slope of the line passing through points </span><span>(−1, 7) and (2, 10) is
</span>
<span>
The equation of a line with slope m passing through a point P(a, b) is given by
(y-b)=m(x-a).
We can consider any of the points (-1, 7), or (2, 10). Let's choose (2, 10):
y-10=1(x-2)
y-10=x-2
y-x=-2+10
y-x=8
Answer: </span><span>C. −x+y=8</span>
The graph that matches the given equation is y≥x-1 is Graph A.
Option: C.
<u>Step-by-step explanation:</u>
The given equation y≥x-1 is a linear inequality equation.
Graphing Linear Inequalities differs from graphing regular linear equations. That is it has certain rules to be followed to draw the graph.
- First, rearrange the equation as y in the left and other terms in the opposite side.
- Check for the line: y= , y≤ and y≥ comes with straight line where as y< and y> comes with a dotted line.
- Shading: If y> greater than or y≥ greater than or equal is present then the space above the line has to be shaded. If y< less than or y≤ less than or equal is present then the space below the line has to be shaded.
For the given equation y≥x-1,
The line will be solid passing through (0,-1) and (3,2) since it has y≥. Also, the region above the line is shaded.
So the graph A is the graph that matches the equation y≥x-1.
