Answer:
3.14159 and so on
Step-by-step explanation:
The question is incomplete, here is the complete question:
Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.
<u>Answer:</u> The half life of the sample of phosphorus-32 is 
<u>Step-by-step explanation:</u>
The equation used to calculate the half life of the sample is given as:

where,
m(t) = amount of sample after time 't' = 356 g
= initial amount of the sample = 500 g
t = time period = 7 days
h = half life of the sample = ?
Putting values in above equation, we get:

Hence, the half life of the sample of phosphorus-32 is 
Answer:
Decreases
Step-by-step explanation:
We need to determine the integral of the DE;



We can solve this by integration by parts on the left side. We expand the fraction 1/P²:

let





Substitute u in:

Therefore the equation is:

We simplify:


As t increases to infinity P will decrease
First, add. 11/10 + 23/10 = 34/10
You can then simplify by finding the greatest common factor (2)
34/2, 10/2 = 17/5, or 3 and 2/5
Andrei is 3 and 2/5 meters tall