Answer and explanation:
The gambler's fallacy is the fallacy of belief that if an event such as a loss occurs more frequently in the past, it is less likely to happen in the future. We assume here that this belief is true, therefore
If she loses, her probability of winning increases =3/4
If she wins, her probability to win is normal =1/2
Given that probability of winning is 1/2
Probability of losing is 1-1/2=1/2
Probability that she wins the tournament is probability that she wins the first two games and loses the last or wins the first game, loses the second and wins the last or loses the first game and wins the last two games or probability that she wins all three games
=1/2*1/2*1/2+1/2*1/2*3/4+1/2*3/4*1/2+1/2*1/2*1/2
=25/48
Probability of winning the tournament if she loses the first game
=1/2*3/4*1/2= 3/16
Note: whenever there is "or" in probability, you add
The true statement about the graph's slope is (c) Its slope is zero.
<h3>How to determine the true statement?</h3>
From the question, we have:
A horizontal line is at y = 2.5.
The horizontal line implies that the cost of lunch do not change
Horizontal lines have a slope of 0
Hence, the true statement about the graph's slope is (c) Its slope is zero.
Read more about slope at:
brainly.com/question/3493733
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20 because when you divide 12 by 3/5 you get 20 use a calculator
Answer:
3 3/4
Step-by-step explanation:
2 1/4 = 9/4
9/4 ÷ 6 = 3/8 1 cookie
3/8 × 10 = 3 3/4 10 cookies
Please give me brainliest ;)
A = 34 x 2 = 68
b = 56/2 = 28
hope it helps
