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Vedmedyk [2.9K]
2 years ago
11

For the function y = 3x, if the input (x) is -2, what is the output (y) ?

Mathematics
1 answer:
Dmitry [639]2 years ago
5 0

Answer:

-6

Step-by-step explanation:

2*-3=-6

rule of thumb: a double negative equals a positive in multiplication or division

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Assume the number of pounds of chocolate consumed in a year is equally likely between 20 and 100 pounds. what is the probability
kramer
Because the probability is uniform (equally likely) between 20 and 100 pounds, the probability distribution is uniform between 80 and 100 pounds, with the value 1/(100-20) = 1/80 chocolates/pound.

Let x =  random variable that represents pounds of chocolate consumed.
Therefore
P(x < 60) = (60 - 20)*(1/80) = 1/2.

Answer: The probability is 1/2.
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Triangles are worth 3 points. Quadrilaterals are worth 4 points. Parallelograms are worth 5 points. Each student identifies and
timurjin [86]

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I agree on janice because if is reliable and brilliant,she can score more than that

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APEX
Natalka [10]
The answer would be D. Conditional Statement 
7 0
3 years ago
Read 2 more answers
(a) Let R = {(a,b): a² + 3b &lt;= 12, a, b € z+} be a relation defined on z+)
grin007 [14]

Answer:

R is an equivalence relation, since R is reflexive, symmetric, and transitive.

Step-by-step explanation:

The relation R is an equivalence if it is reflexive, symmetric and transitive.

The order to options required to show that R is an equivalence relation are;

((a, b), (a, b)) ∈ R since a·b = b·a

Therefore, R is reflexive

If ((a, b), (c, d)) ∈ R then a·d = b·c, which gives c·b = d·a, then ((c, d), (a, b)) ∈ R

Therefore, R is symmetric

If ((c, d), (e, f)) ∈ R, and ((a, b), (c, d)) ∈ R therefore, c·f = d·e, and a·d = b·c

Multiplying gives, a·f·c·d = b·e·c·d, which gives, a·f = b·e, then ((a, b), (e, f)) ∈R

Therefore R is transitive

From the above proofs, the relation R is reflexive, symmetric, and transitive, therefore, R is an equivalent relation.

Reasons:

Prove that the relation R is reflexive

Reflexive property is a property is the property that a number has a value that it posses (it is equal to itself)

The given relation is ((a, b), (c, d)) ∈ R if and only if a·d = b·c

By multiplication property of equality; a·b = b·a

Therefore;

((a, b), (a, b)) ∈ R

The relation, R, is reflexive.

Prove that the relation, R, is symmetric

Given that if ((a, b), (c, d)) ∈ R then we have, a·d = b·c

Therefore, c·b = d·a implies ((c, d), (a, b)) ∈ R

((a, b), (c, d)) and ((c, d), (a, b)) are symmetric.

Therefore, the relation, R, is symmetric.

Prove that R is transitive

Symbolically, transitive property is as follows; If x = y, and y = z, then x = z

From the given relation, ((a, b), (c, d)) ∈ R, then a·d = b·c

Therefore, ((c, d), (e, f)) ∈ R, then c·f = d·e

By multiplication, a·d × c·f = b·c × d·e

a·d·c·f = b·c·d·e

Therefore;

a·f·c·d = b·e·c·d

a·f = b·e

Which gives;

((a, b), (e, f)) ∈ R, therefore, the relation, R, is transitive.

Therefore;

R is an equivalence relation, since R is reflexive, symmetric, and transitive.

Based on a similar question posted online, it is required to rank the given options in the order to show that R is an equivalence relation.

Learn more about equivalent relations here:

brainly.com/question/1503196

4 0
2 years ago
Product of a number and 6​
Marat540 [252]

Hey there!

Your answer is 6n.

"Product of" represents multiplication. So, we can do a number times 6, or "6n".

Have a terrificly amazing day! :D

4 0
3 years ago
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