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topjm [15]
2 years ago
13

I need help on question 3!! geometry unit 5

Mathematics
2 answers:
Oduvanchick [21]2 years ago
6 0

ANSWER:

angle 1 = 180°-35°-36° (angle sum of triangle)

= 109°

angle 3 = 180°-109°(adj angles on a str line)

= 71°

angle 2 = 180°-80°-71°

= 29°

mojhsa [17]2 years ago
5 0

ANSWER:

angle 1 = 180°-35°-36° (angle sum of triangle)

= 109°

angle 3 = 180°-109°(adj angles on a str line)

= 71°

angle 2 = 180°-80°-71°

= 29°

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If AJKL = ARST, which congruences are true by CPCTC? Check all that apply.
evablogger [386]

Based on the CPCTC theorem, the congruences that are true about the given triangles are:

B. ∠K ≅ ∠S

C. KL ≅ ST

D. JK ≅ RS

<h3>What is the CPCTC Theorem?</h3>

According to the CPCTC theorem states that if two triangles are congruent to each other, then, all their corresponding parts will be congruent to each other.

Given that triangles JKL and RST are congruent to each other, therefore:

∠J ≅ ∠R

∠K ≅ ∠S

∠L ≅ ∠T

JK ≅ RS

KL ≅ ST

JL ≅ RT

Therefore, the congruences that would be true by CPCTC are:

B. ∠K ≅ ∠S

C. KL ≅ ST

D. JK ≅ RS

Learn more about the CPCTC theorem on:

brainly.com/question/14706064

#SPJ1

5 0
2 years ago
a water tank holds 24,000 gallons. how many hours will it take for 2/3 of the water to be used if the water is used at an averag
Likurg_2 [28]
In the question, it is already mentioned that the water tank holds = 24,000 gallons
In the given question it is also mentioned that the need is to find the time required to use 2/3 of the total water that the tank holds.
So the need is to find the amount of water that equals 2/3 of the total water in the tank.
Then
Quantity of water that needed to be used = [24000 * (2/3)] gallons
                                                                   = 16000 gallons
In the problem it is also mentioned that the average rate of consumption per day is 650 gallons.
So
650 gallons of water used in = 24 hours
16000 gallons of water will be used in = [(24/650) *16000] hours
                                                             = 590.77 hours
So the time required to consume 2/3 of the total water in the tank is 590.77 hours.
8 0
4 years ago
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