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Vikki [24]
2 years ago
5

Question 7 of 15

Mathematics
1 answer:
IgorC [24]2 years ago
4 0

Answer:

4 is in the tenths place. 9 is in the ones. 5 is in the hundredths. 3 is in the thousandths.

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Solve by Substitution<br> Show Steps<br> −2x + 3y + 5z = −21<br> −4z = 20<br> 6x − 3y = 0
Anarel [89]

−2x + 3y + 5z = −21

−4z = 20

6x − 3y = 0

do -4z=20 first

divide both sides by -4 to get z by itself

-4z/-4=20/-4

z=-5

Use z=-5 into −2x + 3y + 5z = −21

-2x+3y+5(-5)=-21

-2x+3y-25=-21

move -25 to the other side

sign changes from -25 to +25

-2x+3y-25+25=-21+25

-2x+3y=4

6x-3y=0

find x by eliminating y

Add the equations together

-2x+6x+3y+(-3y)=4+0

-2x+6x+3y-3y=4

4x=4

Divide by 4 for both sides

4x/4=4/4

x=1

Use x=1 into 6x − 3y = 0

6(1)-3y=0

6-3y=0

Move 6 to the other side

6-6-3y=0-6

-3y=-6

Divide both sides by -3

-3y/-3=-6/-3

y=2

Answer:

(1, 2, -5)

5 0
4 years ago
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Free points because during this epidemic we need some good in this world
tangare [24]

Answer:

1+1=2

Step-by-step explanation:

8 0
4 years ago
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Adrians recipe for cranberry relish calls for 1 3/4 cups of sugar. He wants to use 1/2 that amount. How much sugar should he use
marusya05 [52]
7/8 cups of sugar is the answer I think
7 0
3 years ago
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What is the simplified form of the expression? k3 [k^7/3] -5
iragen [17]
Simplify the following:
(k^3 k^7)/3 - 5

Combine powers. (k^3 k^7)/3 = k^(7 + 3)/3:
k^(7 + 3)/3 - 5

7 + 3 = 10:
k^10/3 - 5

Put each term in k^10/3 - 5 over the common denominator 3: k^10/3 - 5 = k^10/3 - 15/3:
k^10/3 - 15/3

k^10/3 - 15/3 = (k^10 - 15)/3:
Answer: (k^10 - 15)/3
3 0
3 years ago
Factor the expression 343y^6+64
morpeh [17]

Answer: 343y^6+64= (7y^2+4)(49y^4-28y^2+16)

Step-by-step explanation:

3 0
3 years ago
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