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Elenna [48]
3 years ago
13

What is the empirical formula for a compound if a sample contains 1. 0 g of S and 1. 5 g of O? SO SO3 S2O2 S2O3.

Chemistry
1 answer:
Tcecarenko [31]3 years ago
7 0

The empirical formula of the given compound is \bold{SO_3}.

The correct option is B.

<h3>What is an empirical formula?</h3>

The empirical formula of a chemical compound is the simplest whole-number ratio of atoms contained in the substance.

Given,

1.0 g of S

1.5 g of O

To calculate the empirical formula, we will divide the masses of the elements by their atomic weight.

For sulfur

\bold{\dfrac{1.0}{32} =0.03125\; mol}

For oxygen

\bold{\dfrac{1.5}{16} =0.09375\; mol}

Now, divide the greater value of mole came by the smaller value

\bold{\dfrac{0.09375\; mol}{0.03125\;mol} = 3}

Thus, the empirical formula for the given compound is 1 for S and 3 for O

\bold{SO_3}

Learn more about empirical formula, here:

brainly.com/question/11588623

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What mass of oxygen forms from 71.89 g CO2? Use the periodic table to find molar masses.
Paraphin [41]
Atomic mass C = 12.0107
Atomic mass O= 15.9994
Calculate the molecular mass of the CO2
12.0107 + (2 x 15.9994) = 44.0095

Multiply the mass of CO2 by the conversion factor that relate the O mass to the molecular mass of CO2 to find the mass of O in the 71.89g of CO2

71.89 g CO2 x (2 x 15.9994) / 44.0095 =

52.2703900748702

52.27 g O

8 0
4 years ago
A mixture containing nitrogen and hydrogen weighs 3.48 g and occupies a volume of 7.47 L at 296 K and 1.02 atm. Calculate the ma
Sonbull [250]

Answer:

there is 2% of hydrogen and 98% of nitrogen (mass percent)

Explanation:

assuming ideal gas behaviour

P*V=n*R*T

n= P*V/(R*T)

where P= pressure=1.02 atm , V=volume=7.47 L , T=absolute temperature= 296 K and R= ideal gas constant = 0.082 atm*L/(mole*K)

thus

n= P*V/(R*T) = 1.02 atm*7.47 L/( 296 K * 0.082 atm*L/(mole*K)) = 0.314 moles

since the number of moles is related with the mass m through the molecular weight M

n=m/M

thus denoting 1 as hydrogen and 2 as nitrogen

m₁+m₂ = mt (total mass)

m₁/M₁+m₂/M₂ = n

dividing one equation by the other and denoting mass fraction w₁= m₁/mt , w₂= m₂/mt , w₂= 1- w₁

w₁/M₁+w₂/M₂ = n/mt

w₁/M₁+(1-w₁) /M₂ = n/mt

w₁*(1/M₁- 1/M₂) + 1/M₂ = n/mt

w₁=  (n/mt- 1/M₂) /(1/M₁- 1/M₂)

replacing values

w₁=  (n/mt- 1/M₂) /(1/M₁- 1/M₂) = (0.314 moles/3.48 g - 1/(14 g/mole)) /(1/(1 g/mole)-1/(14 g/mole))= 0.02 (%)

and w₂= 1-w₁= 0.98 (98%)

thus there is 2% of hydrogen and 98% of nitrogen

4 0
3 years ago
6.02 x 10 atoms of cu
Levart [38]

Answer:

what's the question

Explanation:

please edit this or ask in the comments section

7 0
3 years ago
The density of gold is 19.3 g/cm³. What is the mass of 11.3 cm³ of gold?
telo118 [61]

Answer:

218.09g

Explanation:

the formula for density is mass/volume

you have volume so rlly what you have is 19.3g/cm3=m/11.3cm3

so mass equals density x volume

and 19.3 x 11.3 = 218.09

4 0
3 years ago
1. Choose the alkyl halide(s) from the following list of C6H13Br isomers that meet each criterion below. 1) 1-bromohexane 2) 3-b
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Answer:

See explanation

Explanation:

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the compound that gives the fastest SN1 reaction- 3-bromo-3-methylpentane

the compound(s) that undergo an SN1 reaction to give rearranged products- 1-bromo-2,2-dimethylbutane

the compound that is least reactive to sodium methoxide in methanol -

3-bromo-3-methylpentane

the compound(s) that can exist as diastereomers - 3-bromo-3-methylpentane

the compound(s) that can exist as enantiomers- 3-bromo-2-methylpentane

6 0
3 years ago
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