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Nitella [24]
2 years ago
10

Joaquin and Trisha are playing a game in which the lower median wins the game. Their scores are shown below. Joaquin’s scores: 7

5, 72, 85, 62, 58, 91 Trisha’s scores: 92, 90, 55, 76, 91, 74 Which supports the conclusion that Joaquin won the game? Joaquin won because the median of his scores is 73. 5 and the median of Trisha’s scores is 83. Joaquin won because the median of his scores is 83 and the median of Trisha’s scores is 73. 5. Trisha won because the median of her scores is 73. 5 and the median of Joaquin’s scores is 83. Trisha won because the median of her scores is 83 and the median of Joaquin’s scores is 73. 5.
Mathematics
1 answer:
ioda2 years ago
6 0

The conclusion that supports that Joaquin wins the game is:

Joaquin won because the median of his scores is 73.5 and the median of Trisha’s scores is 83.

<h3>What is the median of a dataset?</h3>

In a data set involving an array of numbers, the median is usually the middle number after the data sets are arranged in order of magnitude from the lowest to the highest.

From the given information:

  • Joaquin’s scores: 75, 72, 85, 62, 58, 91
  • Trisha’s scores: 92, 90, 55, 76, 91, 74

Now, by rearranging the array of numbers, we have:

  • Joaquin’s scores: 58, 62, 72, 75, 85, 91
  • Trisha’s scores: 55, 74, 76, 90, 91, 92
  • The median score of Joaquin is = (72 + 75)/2 = 73.5
  • The median score of Trisha is = (76 + 90)/2 = 83

Therefore, we can conclude that Joaquin won because the median of his scores is 73.5 and the median of Trisha’s scores is 83.

Learn more about the median of a data set here:

brainly.com/question/23962563

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Find the sum of the first 20 terms of an arithmetic sequence with an 18th term of 8.1 and a common difference of 0.25.
il63 [147K]

The sum of the first 20 terms of an arithmetic sequence with the 18th term of 8.1 and a common difference of 0.25 is 124.5

Given,

18th term of an arithmetic sequence = 8.1

Common difference = d = 0.25.

<h3>What is an arithmetic sequence?</h3>

The sequence in which the difference between the consecutive term is constant.

The nth term is denoted by:

a_n = a + ( n - 1 ) d

The sum of an arithmetic sequence:

S_n = n/2 [ 2a + ( n - 1 ) d ]

Find the 18th term of the sequence.

18th term = 8.1

d = 0.25

8.1 = a + ( 18 - 1 ) 0.25

8.1 = a + 17 x 0.25

8.1 = a + 4.25

a = 8.1 - 4.25

a = 3.85

Find the sum of 20 terms.

S_20 = 20 / 2 [ 2 x 3.85 + ( 20 - 1 ) 0.25 ]

         = 10 [ 7.7 + 19 x 0.25 ]

         = 10 [ 7.7 + 4.75 ]

         = 10 x 12.45

         = 124.5

Thus the sum of the first 20 terms of an arithmetic sequence with the 18th term of 8.1 and a common difference of 0.25 is 124.5

Learn more about arithmetic sequence here:

brainly.com/question/25749583

#SPJ1

8 0
1 year ago
The bill for a stay in a hotel was $188 including $15 tax. what percent of the bill was the tax?
ziro4ka [17]
\frac{15}{188}\cdot100\%=\\\\\frac{1500}{188}\%\approx8\%\\\\The\ tax\ was\ about\ 8\%\ of \ bill.
4 0
3 years ago
Find the measure of 2.<br> 63° 117°<br> 62 = [?]<br> Enter
forsale [732]

Answer:

63°

Step-by-step explanation:

Angle <2 and the angle with measure of 63 are alternate exterior angles and has same measurement.

7 0
3 years ago
How much longer is the hypotenuse of the triangle than its shorter leg?
RUDIKE [14]

This is an incomplete question, here is a complete question and image is also attached below.

How much longer is the hypotenuse of the triangle than its shorter leg?

a. 2 ft

b. 4 ft

c. 8 ft

d. 10 ft

Answer : The correct option is, (b) 4 ft

Step-by-step explanation:

Using Pythagoras theorem in ΔACB :

(Hypotenuse)^2=(Perpendicular)^2+(Base)^2

(AB)^2=(AC)^2+(BC)^2

Given:

Side AC = 6 ft

Side BC = 8 ft

Now put all the values in the above expression, we get the value of side AB.

(AB)^2=(6)^2+(8)^2

AB=\sqrt{(6)^2+(8)^2}

AB=10ft

Now we have to calculate the how much longer is the hypotenuse of the triangle than its shorter leg.

Difference = Side AB - Side AC

Difference = 10 ft - 6 ft

Difference = 4 ft

Therefore, the 4 ft longer is the hypotenuse of the triangle than its shorter leg.

5 0
3 years ago
Read 3 more answers
I need some help with this calculus 1 question.
Cerrena [4.2K]

Answer:

(a) f'(1)=-4

(b) y+4x-4=0

Step-by-step explanation:

<u>Tangent Line of a Function</u>

Given f(x) a real differentiable function in x=a, the slope of the tangent line of the function in x=a is given by f'(x=a). Where f' is the first derivative of f.

We are given

y=x-x^5

The derivative is

y'=1-5x^4

(a) The slope of the tangent line at (1,0) is

f'(1)=1-5\cdot 1^4=-4

f'(1)=-4

(b) The equation of the tangent line can be found with the general formula of the line:

y-y_o=m(x-x_o)

Where m is the slope and the point (xo,yo) belongs to the line. We have m=-4, xo=1, yo=0, thus

y-0=-4(x-1)

Or, equivalently

y+4x-4=0

3 0
3 years ago
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