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dedylja [7]
2 years ago
12

Find the volume of the triangular prism ​

Mathematics
1 answer:
andrew-mc [135]2 years ago
7 0

Answer:

32inch³

Step-by-step explanation:

formula= ½bh²

½×4×4×4

½×64

= 64/2

=32inches³

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Find the solution of y = 6x + 1 for x = 5.
user100 [1]
Y=6x+1
y=6(5)+1
y=30+1
y=31
D. (5, 31)
hope this helps!
4 0
4 years ago
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Can someone help me on this question.
Temka [501]
46! Because 5 times 3 is 15 and the two big rectangles are equal, that’s 15+15. (30) 5x1 is 5 and THERES two equal things like that so 5+5 (10). 3x1 is 3 and THERES also two equal things so add 3+3. (6) add 30+10+6 which makes 46! :)

7 0
3 years ago
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PLEASE HELP ITS URGENT. I’ll give lots of points who helps !! Please
Molodets [167]

Answer:

D:21

Step-by-step explanation:

Use the vertical angles equation.

4x + 13 = 5x - 8

Subtract 4x from 5x.

5x - 4x = x

13 = x - 8

Add 8 on both dies.

13 + 8 = 21

x = 21

JKLM has x that equals 21.

<JKLM and <LMJK equal 97 degrees.

Hope it helped!

7 0
3 years ago
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sara says. "if you subtract 14 from my number and multiply the difference by -4, the result is -80." What is Sara's number?​
statuscvo [17]

Answer:

6

Step-by-step explanation:

-80/-4=20+14=6

5 0
4 years ago
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If you had 1052 toothpicks and were asked to group them in powers of 6, how many groups of each power of 6 would you have? Put t
sukhopar [10]

1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

The number 1052, written as a base 6 number is 4512

Given: 1052 toothpicks

To do: The objective is to group the toothpicks in powers of 6 and to write the number 1052 as a base 6 number

First we note that, 6^{0}=1,6^{1}=6,6^{2}=36,6^{3}=216,6^{4}=1296

This implies that 6^{4} exceeds 1052 and thus the highest power of 6 that the toothpicks can be grouped into is 3.

Now, 6^{3}=216 and 216\times 5=1080, 216\times 4=864. This implies that 216\times 5 exceeds 1052 and thus there can be at most 4 groups of 6^{3}.

Then,

1052-4\times6^{3}

1052-4\times216

1052-864

188

So, after grouping the toothpicks into 4 groups of third power of 6, there are 188 toothpicks remaining.

Now, 6^{2}=36 and 36\times 5=180, 36\times 6=216. This implies that 36\times 6 exceeds 188 and thus there can be at most 5 groups of 6^{2}.

Then,

188-5\times6^{2}

188-5\times36

188-180

8

So, after grouping the remaining toothpicks into 5 groups of second power of 6, there are 8 toothpicks remaining.

Now, 6^{1}=6 and 6\times 1=6, 6\times 2=12. This implies that 6\times 2 exceeds 8 and thus there can be at most 1 group of 6^{1}.

Then,

8-1\times6^{1}

8-1\times6

8-6

2

So, after grouping the remaining toothpicks into 1 group of first power of 6, there are 2 toothpicks remaining.

Now, 6^{0}=1 and 1\times 2=2. This implies that the remaining toothpicks can be exactly grouped into 2 groups of zeroth power of 6.

This concludes the grouping.

Thus, it was obtained that 1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

Then,

1052=4\times6^{3}+5\times6^{2}+1\times6^{1}+2\times6^{0}

So, the number 1052, written as a base 6 number is 4512.

Learn more about change of base of numbers here:

brainly.com/question/14291917

6 0
3 years ago
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