Question

Need Help NO LINKS please Special Right Triangles (Radical Answers)

Answer 1

Answer:

x =  $2\sqrt{2}$ (or $\frac{2\sqrt{2} }{1}$ if it needs to be represented as a rational denominator)

Step-by-step explanation:

We know that;

1.) This triangle is equilateral, and because of the line segment it's divided into 2 right triangles.

2.) The base of the whole triangle would be 4, and the base of the right triangle would be 2, since the base is cut in half with a mid point.

Therefore we can say;

A² + B² = C²

x² + 2² = 4²

x² + 4 = 16

x² = 16 - 4

x² = 8

x = $\sqrt{8}$

Simplifying this further would be;

$\sqrt{8}$ = $\sqrt{4} * \sqrt{2}$

$\sqrt{8}$ = $2\sqrt{2}$ (or $\frac{2\sqrt{2} }{1}$ if it needs to be represented as a rational denominator)

Hope this helps!