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viva [34]
2 years ago
6

Please help (images below)

Mathematics
1 answer:
Kay [80]2 years ago
5 0

Answer:

2) D

because:

\frac{9}{1}  \times 4 \\  9 \times 4 \\ 36  \: is \: not \: equal \: to \: 4

4) B

because:

\frac{5}{5}  \times 8 \\ 1 \times 8 \\ 8 \: is \: equal \: to \: 8

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Which of the following is the value of f(-4) in the function f(x) = -2x - 3?<br><br> no links
Scilla [17]

Answer:

5

Step-by-step explanation:

f(-4)= -2(-4)-3

=8-3

=5

8 0
3 years ago
Family has an annual income of ​$23 comma 400. Of​ this, one fourth
denis23 [38]

Amount spent for food = $5850, housing = $4680, clothing = $2340, savings = $2600, taxes = $5850, expenses = $2080.

<u>Step-by-step explanation:</u>

Step 1:

Given details are Total Income = $23,400

Step 2:

Amount spent for food, F= 1/4th of 23,400 = 1/4 \times 23400

= $5850

Step 3:

Amount spent for housing, H = 1/5th of 23,400 = 1/5 \times23400

= $4680

Step 4:

Amount spent for clothing, C = 1/10th of 23,400 = 1/10 \times 23400 = $2340

Step 5:

Amount spent for savings, S = 1/9th of 13,400 = 1/9\times 23400 = $2600

Step 6:

Amount spent for taxes, T = 1/4th of 23,400 =  1/4 \times 23400 =$5850

Step 7:

Find amount spent on other expenses by totaling all expenditures and subtracting from the annual income.

Annual Income = F + H + C + S + T + E

Amount spent on other expenses, E = 23400 - (5850 + 4680 + 2340 + 2600 + 5850)

E = 23400 - 21320

E = $2080

5 0
3 years ago
Marla is making a fence to go
Kamila [148]

Answer:

16 feet of fencing

Step-by-step explanation:

This equation is essentially asking us the perimeter of the fence. If you add 5+3+5+3 you get the sum of 16

5 0
2 years ago
Read 2 more answers
Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z
kompoz [17]

a.

f_{X,Y,Z}(x,y,z)=\begin{cases}Ce^{-(0.5x+0.2y+0.1z)}&\text{for }x\ge0,y\ge0,z\ge0\\0&\text{otherwise}\end{cases}

is a proper joint density function if, over its support, f is non-negative and the integral of f is 1. The first condition is easily met as long as C\ge0. To meet the second condition, we require

\displaystyle\int_0^\infty\int_0^\infty\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz=100C=1\implies \boxed{C=0.01}

b. Find the marginal joint density of X and Y by integrating the joint density with respect to z:

f_{X,Y}(x,y)=\displaystyle\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dz=0.01e^{-(0.5x+0.2y)}\int_0^\infty e^{-0.1z}\,\mathrm dz

\implies f_{X,Y}(x,y)=\begin{cases}0.1e^{-(0.5x+0.2y)}&\text{for }x\ge0,y\ge0\\0&\text{otherwise}\end{cases}

Then

\displaystyle P(X\le1.375,Y\le1.5)=\int_0^{1.5}\int_0^{1.375}f_{X,Y}(x,y)\,\mathrm dx\,\mathrm dy

\approx\boxed{0.12886}

c. This probability can be found by simply integrating the joint density:

\displaystyle P(X\le1.375,Y\le1.5,Z\le1)=\int_0^1\int_0^{1.5}\int_0^{1.375}f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz

\approx\boxed{0.012262}

7 0
3 years ago
Hi where is mc donalds?
Nikitich [7]
Maybe you can use your gps lololol
5 0
2 years ago
Read 2 more answers
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