Answer:
the probability that five randomly selected students will have a mean score that is greater than the mean achieved by the students = 0.0096
Step-by-step explanation:
From the five randomly selected students ; 160, 175, 163, 149, 153
mean average of the students = 160+175+163+149+153/5
= mean = x-bar = 800/5
mean x-bar = 160
from probability distribution, P(x-bar > 160) = P[ x-bar - miu / SD > 160 -150.8 /3.94]
P( Z>2.34) = from normal Z-distribution table
= 0.0096419
= 0.0096
hence the probability that five randomly selected students will have a mean score that is greater than the mean achieved by the students = 0.0096
where SD = standard deviation = 3.94 and Miu = 150.8
Answer:
20
Step-by-step explanation:
A=20
Answer:
The answer to your question is:
x = -10; y = 8
Step-by-step explanation:
Solve equations by elimination method
2x + 3y = 4 (1)
x + 2y = 6 (2)
Multiply 2 by -2
2x + 3y = 4
-2x - 4y = -12
-y = -8
y = 8
Substitute y in (2)
x + 2(8) = 6
x = 6 - 16
x = -10
Answer:
1 + 1 + 2 + 2 + 3 + 3 + 4 + 4 + 5 + 5 + 6 + 6 + 7 + 7 + 8 + 8 + 9 + 9 + 10 + 10 - 90 = 20
Step-by-step explanation:
