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chubhunter [2.5K]
1 year ago
8

Using suitable identity evaluate the following : 98^3

Mathematics
1 answer:
stiv31 [10]1 year ago
6 0

941,192

Steps:

(a-b)^3=a^3-b^3-3a^2b+3ab

\begin{gathered} (98)^3=(100-2)^3 \\ (100-2)^{3\text{ }}=(100)^3-(2)^3-3\cdot(100)^2\cdot2+3\cdot100\cdot2^2\text{ } \\ (100)^3-(2)^3-3\cdot(100)^2\cdot2+3\cdot100\cdot2^2\text{ = 1,0}00,000\text{ - 3 - 60,000 +1,200} \\ \text{ 1,0}00,000\text{ - 3 - 60,000 +1,200 = 941,192} \end{gathered}

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Answer:

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n+15=0

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Let's check both results

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