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1 year ago

Using suitable identity evaluate the following : 98^3

Mathematics

1 answer:

stiv31 [10]1 year ago

6 0

941,192

Steps:

$(a-b)^3=a^3-b^3-3a^2b+3ab$

$\begin{gathered} (98)^3=(100-2)^3 \\ (100-2)^{3\text{ }}=(100)^3-(2)^3-3\cdot(100)^2\cdot2+3\cdot100\cdot2^2\text{ } \\ (100)^3-(2)^3-3\cdot(100)^2\cdot2+3\cdot100\cdot2^2\text{ = 1,0}00,000\text{ - 3 - 60,000 +1,200} \\ \text{ 1,0}00,000\text{ - 3 - 60,000 +1,200 = 941,192} \end{gathered}$

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3 years ago

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Step-by-step explanation:

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3 years ago

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3 years ago

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MrRissso [65]

Answer:

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Step-by-step explanation:

To solve this polynomial, you need to distribute/multiply, (x+2) with (2x+3).

You would first multiply (x) with 2x and 3. This would give you 2x² and 3x. You would then multiply 2 with 2x and 3. This would give you 4x and 6. You then add the like-terms, which are 3x and 4x, which gives you 7x. This would give you your final expression of 2x² +7x + 6.

(x+2)(2x+3)

2x²+ 3x + 4x + 6

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3 years ago

Read 2 more answers

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Natali5045456 [20]

Answer:

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Step-by-step explanation:

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Problems of normal distributions can be solved using the z-score formula.

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