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2 years ago

Solve the system of equation

Mathematics

1 answer:

kherson [118]2 years ago

8 0

Answer:

The answer to your question is:

x = -10; y = 8

Step-by-step explanation:

Solve equations by elimination method

2x + 3y = 4 (1)

x + 2y = 6 (2)

Multiply 2 by -2

2x + 3y = 4

-2x - 4y = -12

-y = -8

y = 8

Substitute y in (2)

x + 2(8) = 6

x = 6 - 16

x = -10

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3 years ago

"There are 15 questions on an exam. In how many ways can the exam be answered with exactly 8 answers correct?"

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Answer:

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Step-by-step explanation:

The order is not important.

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Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

"There are 15 questions on an exam. In how many ways can the exam be answered with exactly 8 answers correct?"

Combinations of 8 questions from a set of 15. So

$C_{15,8} = \frac{15!}{8!(15-8)!} = 6435$

The exam can be answered with exactly 8 answers correct in 6435 ways.

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2 years ago

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