Answer:
(the statement does not appear to be true)
Step-by-step explanation:
I don't think the statement is true, but you CAN compute the intercepted arc from the angle.
Note that BFDG is a convex quadrilateral, so its angles sum to 360. Since we know the inscribed circle touches the angle tangentially, angles BFD and BGD are both right angles, with a measure of 90 degrees.
Therefore, adding the angles together, we have:
alpha + 90 + 90 + <FDG = 360
Therefore, <FDG, the inscribed angle, is 180-alpha (ie, supplementary to alpha)
Answer:
50. in this graph it is talking about the rate it changed from 1 to 4
Step-by-step explanation:
f(b)-f(a)/b-a
270-120/4-1
50
5+2=7 which means there will be 7 zeros so it is 10000000 times greater than
When a teacher gives a test with questions that fall into 3 levels of difficulty (easy, moderate, and hard) The scoring method that would best allow her to identify the students who need help is:
B. weight each question by its difficulty: 1 for easy, 2 for moderate, and 3 for hard.
24ft/s for the 1st second then it'd be 9.8mp/s which is the speed of velocity towards earth, so the 24ft/s - the 9.8 would be 14.2ft/s which is the second, the third would then be 4.4 after again subtracting 9.8. That is as far as I got, hope that helps even slightly
