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2 years ago

Tom spends 1 hour bathing a day.

Mathematics

2 answers:

GuDViN [60]2 years ago

7 0

Answer: she doesnt

Step-by-step explanation:

they spend the same amount of time bathing

Andreas93 [3]2 years ago

5 0

Answer:

They both spend the same amount of time bathing within the 7 days.

Step-by-step explanation:

Since they both spend an hour bathing each day, within the 7 days, they would have bathed the same amount of time as well.

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Find the area of this triangle... Round to the nearest tenth and include units in your answer

alina1380 [7]

Answer:

36 m^2

Step-by-step explanation:

the formula for the area of a triangle is 1/2•b•h

so you’re going to do 1/2 times 12 times 6 to get the area of 36 m^2

4 0

3 years ago

Does anyone have a website to cheat on

lorasvet [3.4K]

Answer:

No i do for other stuff but not this and the answer is 18

Step-by-step explanation:

5 0

3 years ago

An angle measuring 3.5 radians is equal to which of the angle measures given below? Check all that apply.

Tresset [83]

The answers are B & C.

First thing to d o is convert Radians to Degrees. 1 radians = 180/pi . So, 3.5 radians times 180 divided by $\pi$ = 200.5352283 or which could be rounded of to 200.54. Thus, confirming choice letter C and negating choices A and D.

Next thing to check is choice letter B. To do this, we need to convert the decimal value of the computed answer which is 0.5352283 to minutes and seconds by the following conversion factors.

1 degree = 60 mins
1 minute = 60 seconds

Now, we multiply 0.5352283 by 60 to get 32.113698 minutes, thus 32 minutes
then multiply 0.113698 by 60 to get 6.82188 ~ 7 seconds.

therefore, conversion would yield an answer 200 degrees 32 minutes and 7 seconds.

6 0

3 years ago

Problem: A piece of farmland is a watering plot of land in a circular pattern. A sewer line needs to be installed from a new hou

Musya8 [376]

The entry and exit points of (2, 3), and (12, 6), and 200 ft. extension of the sprinkler system gives;

(1) The sewer line crosses the farmland at (6.53, 4.36), and (8.48, 4.9)

(2) The longest installable sprinkler system is approximately 172.4 feet

<h3>How can the points where the line crosses the farmland be found?</h3>

1. The slope of the sewer line is found as follows;

m = (6 - 3)/(12 - 2) = 3/10 = 0.3

The equation of the sewer line can be expressed in point and slope form as follows;

(y - 3) = 0.3×(x - 2)

y = 0.3•x - 0.6 + 3

y = 0.3•x + 2.4

The equation of the circumference of the sprinkler can be expressed as follows;

(x - 8)² + (y - 3)² = 2²

Therefore;

(x - 8)² + (0.3•x + 2.4 - 3)² = 2²

Solving gives;

x= 6.53, or x = 8.48

y = 0.3×6.53 + 2.4 = 4.36

y = 0.3×8.48 + 2.4 = 4.9

Therefore;

The sewer line crosses the farmland at (6.53, 4.36), and (8.48, 4.9)

2. When the farmland does not cross the sewer line, we have;

sewer line is tangent to circumference of farmland

Slope of radial line from center of the land is therefore;

m1 = -1/0.3

Equation of the radial line to the point the sewer line is tangent to the circumference is therefore;

y - 3 = (-1/0.3)×(x - 8)

Which gives;

y = (-1/0.3)×(x - 8) + 3

The x-coordinate is therefore;

0.3•x + 2.4 = (-1/0.3)×(x - 8) + 3

x ≈ 7.5

y = 0.3 × 7.5 + 2.4 ≈ 4.65

The longest sprinkler system is therefore;

d = √((7.5 - 8)² + (4.65 - 3)²) ≈ 1.724

Which gives;

The longest sprinkler system is 1.724 × 100 ft. ≈ 172.4 ft.

Learn more about the equation of a circle here:

brainly.com/question/10368742

#SPJ1

3 0

2 years ago

Trig proofs with Pythagorean Identities.

lorasvet [3.4K]

To prove:

$$\frac{1}{1-\cos x}-\frac{\cos x}{1+\cos x}=2 \cot ^{2} x+1$

Solution:

$$LHS = \frac{1}{1-\cos x}-\frac{\cos x}{1+\cos x}$

Multiply first term by $\frac{1+cos x}{1+cos x}$ and second term by $\frac{1-cos x}{1-cos x}$ .

$$= \frac{1(1+\cos x)}{(1-\cos x)(1+\cos x)}-\frac{\cos x(1-\cos x)}{(1+\cos x)(1-\cos x)}$

Using the identity: $(a-b)(a+b)=(a^2-b^2)$

$$= \frac{1+\cos x}{(1^2-\cos^2 x)}-\frac{\cos x-\cos^2 x}{(1^2-\cos^2 x)}$

Denominators are same, you can subtract the fractions.

$$= \frac{1+\cos x-\cos x+\cos^2 x}{(1^2-\cos^2 x)}$

Using the identity: $1-\cos ^{2}(x)=\sin ^{2}(x)$

$$= \frac{1+\cos^2 x}{\sin^2x}$

Using the identity: $1=\cos ^{2}(x)+\sin ^{2}(x)$

$$=\frac{\cos ^{2}x+\cos ^{2}x+\sin ^{2}x}{\sin ^{2}x}$

$$=\frac{\sin ^{2}x+2 \cos ^{2}x}{\sin ^{2}x}$ ------------ (1)

$RHS=2 \cot ^{2} x+1$

Using the identity: $\cot (x)=\frac{\cos (x)}{\sin (x)}$

$$=1+2\left(\frac{\cos x}{\sin x}\right)^{2}$

$$=1+2\frac{\cos^{2} x}{\sin^{2} x}$

$$=\frac{\sin^2 x + 2\cos^{2} x}{\sin^2 x}$ ------------ (2)

Equation (1) = Equation (2)

LHS = RHS

$$\frac{1}{1-\cos x}-\frac{\cos x}{1+\cos x}=2 \cot ^{2} x+1$

Hence proved.

5 0

3 years ago