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svetlana [45]
3 years ago
5

If and object undergoes a change in momentum of 12 kg*m/s over a 10

Physics
1 answer:
iris [78.8K]3 years ago
8 0

The magnitude of the force exerted on this object is 1.2 Newton.

<u>Given the following data:</u>

  • Change in momentum = 12 Kgm/s.
  • Time = 10 seconds.

<h3>What is impulse?</h3>

In Science, the impulse that is experienced by an object is always equal to the change in momentum of the object, due to the force acting on an object.

Mathematically, impulse is given by this formula:

Impulse = change\;in\;momentum\\\\Force \times time = m \Delta V

Substituting the given parameters into the formula, we have:

Force \times 10=12\\\\Force =\frac{12}{10}

Force = 1.2 Newton.

Read more on force here: brainly.com/question/16750406

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In the first stage of a two-stage rocket, the rocket is fired from the launch pad starting from rest but with a constant acceler
AnnZ [28]

Answer:

3091.56

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s² (positive downward and negative upward)

s=ut+\frac{1}{2}at^2\\\Rightarrow s=0\times 25+\frac{1}{2}\times 3.5\times 25^2\\\Rightarrow s=1093.75\ m

Distance traveled in the first stage is 1093.75 m

v=u+at\\\Rightarrow v=0+3.5\times 25\\\Rightarrow v=87.5\ m/s

Velocity at the end of first stage is 87.5 m/s

v=u+at\\\Rightarrow a=\frac{v-u}{t}\\\Rightarrow a=\frac{132.5-87.5}{10}\\\Rightarrow a=4.5\ m/s^2

Acceleration of the second stage is 4.5 m/s²

s=ut+\frac{1}{2}at^2\\\Rightarrow s=87.5\times 10+\frac{1}{2}\times 4.5\times 10^2\\\Rightarrow s=1100\ m

Distance traveled in the second stage is 1100 m

v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-132.5^2}{2\times -9.81}\\\Rightarrow s=894.81\ m

Distance traveled after the second stage has stopped firing is 894.81 m

Total height the rocket reached = 1093.75+1100+897.81 = 3091.56 m

3 0
3 years ago
how does the location of semiconductors on the periodic table differ from the locations of other element families​
Mekhanik [1.2K]

Answer:

Semi conductors are part of the fourth group in periodic table.

Explanation:

Periodic table is the arrangement of chemical elements on the basis of their atomic number. So all the elements with  respective valence electrons are placed in thir respective groups. . All the elements with valence electrons four are placed in the fourth group .Semi conductors is the common name given to the elements of 4th group. These elements dont have the tendency to either donate or accept.

The group 3 elements have three electrons in their valence shell and  hence have a tendency to donate. Whereas the group 5 elements having five valence electrons accept to satisfy thir octet. The semi conductors exist between 3rd and 5th groups exhibiting different properties according to the temperatures and excitations provided.

3 0
3 years ago
In serving, a tennis player accelerates a 59 g tennis ball horizontally from rest to a speed of 34 m/s Assuming that the acceler
Akimi4 [234]

Answer:

The magnitude of the force exerted on the ball by the racquet is 94.73 N.

Explanation:

The force exerted on the ball is the following:

F = ma

Where:

m: is the mass of the ball = 59 g

a: is the acceleration

The acceleration of the ball can be found with the following kinematic equation:

v_{f}^{2} = v_{0}^{2} + 2ad

Where:

d: is the distance = 0.36 m

v_{f}: is the final speed = 34 m/s

v_{0}: is the initial speed = 0 (it start from rest)

Hence, the acceleration is:

a = \frac{v_{f}^{2}}{2d} = \frac{(34 m/s)^{2}}{2*0.36 m} = 1605.6 m/s^{2

Finally, the force is:

F = ma = 59 \cdot 10^{-3} kg*1605.6 m/s^{2} = 94.73 N    

Therefore, the magnitude of the force exerted on the ball by the racquet is 94.73 N.                                

                                                                 

I hope it helps you!                                                              

6 0
3 years ago
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