Answer:
270 m
Explanation:
Given:
v₀ = 63 m/s
a = 2.8 m/s²
t = 4.0 s
Find: Δx
Δx = v₀ t + ½ at²
Δx = (63 m/s) (4.0 s) + ½ (2.8 m/s²) (4.0 s)²
Δx = 274.4 m
Rounded to two significant figures, the displacement is 270 meters.
Answer: an epiphyseal line
Explaination: The epiphyseal plate is a zone of hyaline cartilage between the epiphysis and diaphysis of a long bone. When the cartilage is replaced with bone and the plate closes, the bone has reached its maximum length. This is called the epiphyseal line.
The tension in the cables as the elevator travel upwards is 1,960 N.
The given parameters:
- Mass of the elevator, m = 200 kg
<h3>Newton's second law of motion;</h3>
Newton's second law of motion states that the force applied to an object is directly proportional to the product of mass and acceleration of the object.
The tension in the cables as the elevator travel upwards is calculated by applying Newton's second law of motion as shown below;
T = ma + mg
where;
- a is the acceleration of the elevator
- g is the acceleration due to gravity
At constant velocity, acceleration is zero (a = 0)
T = m(0) + mg
T = mg
T = 200 x 9.8
T= 1,960 N
Thus, the tension in the cables as the elevator travel upwards is 1,960 N.
Learn more about Newton's second law here: brainly.com/question/3999427
Well, I think the answer would be 4 meters because the speed is in meters per second and the frequency is 5 waves every 2 seconds.
Wavelength = Speed/Frequency
I think the frequency is 2.5 waves a second but that's not something I'm 100% sure about.
I hope this helps though.
