Answer:
6.575
Explanation:
T1 = 30C = 30 + 273 = 303 K
T2 = - 10 C = - 10 + 273 = 263 K
The coefficient of performance of heat pump
k = T2 / (T1 - T2)
k = 263 / (303 - 263) = 6.575
Answer:
Total energy saving will be 0.8 KWH
Explanation:
We have given there are 50 long light bulbs of power 100 W so total power of 50 bulb = 100×50 = 5000 W = 5 KW
30 bulbs are of power 60 W
So total power of 30 bulbs = 30×60 = 1800 W = 1.8 KW
Total power of 80 bulbs = 1.8+5 = 6.8 KW
Total time = 3 hour
We know that energy 
Now power of each CFL bulb = 25 W
So power of 80 bulbs = 80×25 = 2000 W = 2 KW
Energy of 80 bulbs = 2×3 = 6 KWH
So total energy saving = 6.8-6 = 0.8 KWH
Answer:
conduction,convection,radiation