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2 years ago

Help please this makes no sense

Mathematics

1 answer:

Degger [83]2 years ago

5 0

Answer:

ST = 7.1 in

Step-by-step explanation:

we can use SOH-CAH-TOA because we've got a right triangle

side ST would be 'adjacent'

side TU would be the 'hypotenuse'

so we use Cosine because that's used when you're dealing with adjacent and hypotenuse:

cos 42° = ST/9.5

ST = cos 42° × 9.5

ST = 7.1

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masya89 [10]

Neither P, nor A are on the sketch
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and A=(0,1)

P belongs to the line going through (1,0) and B(0,y)
but we don't know the y-coordinate of B 

the triangle is right and isosceles, so pythagoras a²+a²=2² ... 2a²=4 ... a²=2 ... a=sqrt2 
now look at the right triangle BOA
his hypotenuse is AB=sqrt2 and the the kathete OA is 1 
so y²+1²=(sqrt2)² ... y²+1=2 ... y²=1.. y=1
so the coordinates of B are (0,1)

the line going through (1,0) and (0,1) is L(x)=-x+1

P belongs to this line, so the coordinates of P are P(x,-x+1) (0<x<1)

b) so if that's P, the height of the rectangle is -x+1 and the width=2x
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I hope my answer has come to your help. Thank you for posting your question here in Brainly.

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You are in charge of managing the advertising for a restaurant. You are able to buy up to 62 advertisements a month, and your da

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Answer:

Greatest number of newspaper ads = 59

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Step-by-step explanation:

It is given that we should buy at least 5 newspapers for every 3 television ads.

So, after purchasing 3 television ads, we can buy any number of television ads but the number should be greater than 5.

Since, the maximum is 62, we can buy 59 newspaper ads. (Note that we have already bought 3 television ads).

For every 3 television ads, we should buy 5 newspaper ads. So,

For the purchase of 3 television ads, we should buy the minimum of 5 newspaper ads.

For the purchase of 2(3) television ads, we should buy the minimum of 2(5) newspaper ads.

For the purchase of 3(3) television ads, we should buy the minimum of 3(5) newspaper ads.

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For the purchase of 7(3) = 21 television ads, we should buy the minimum of 7(5) = 35 newspaper ads.

So, totally 21+35 = 56 ads.

For the remaining 6 ads, if we buy 3 television ads, we should buy 5 newspaper ads.

So, we can buy 2 television ads and 4 newspaper ads.

Hence, we can buy the maximum of 21+2 = 23 television ads.

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