Given:
Sides of triangles in the options.
To find:
Which could NOT be the lengths of the sides of a triangle.
Solution:
Condition for triangle:
Sum of two smaller sides of a triangle must be greater than the longest side.
In option A,

Sides 5 in, 5 in, 5 in are the lengths of the sides of a triangle.
In option B,

Sides 10 cm, 15 cm, 20 cm are the lengths of the sides of a triangle.
In option C,

Sides 3 in, 4 in, 5 in are the lengths of the sides of a triangle.
In option D,

Since, the sum of two smaller sides is less than the longest side, therefore the sides 8 ft, 15 ft, 5 ft are not the lengths of the sides of a triangle.
Therefore, the correct option is D.
Answer:
See the three attached images.
Step-by-step explanation:
image1 shows the intersection of b and c:
. (green "football")
image2 shows the <u>complement</u> of a (outside a):
(yellow)
image3 shows the intersection of those sets:
(green "football with a bite out of it") :-)
For example: Square has dimension a
A = a² and if every dimension is multiplied by k new dimension would be:
A 1 = k² a² = k² A.
Or the area of rhombus: A = d1 * d 2 / 2
New area is: A 1 = k d 1 * k d 2 / 2 = k² A
Answer: If every dimension of two-dimensional figure is multiplied by k, the area is multiplied by k².
Answer:
-8 square root 2
Step-by-step explanation: