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3 years ago

What is -3 2/3 times (-2 1/4)?

1 answer:

5 0

(-3 2/3) * (-2 1/4) ...turn to improper fractions
-11/3 * - 9/4 = ....now multiply straight across,and neg. x neg. = pos
99/12 reduces to 33/4 or 8 1/4

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sesenic [268]

Answer:

Explanation:

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3 years ago

Find the median, mean, and range.

RSB [31]

Hey there!

The median is 8.5

The mean is 7

The range is 11

Hope this helps!

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4 years ago

You have a six-sided die that you roll once. Let Ri denote the event that the roll is i. Let G j denote the event that the roll

Misha Larkins [42]

Answer:

a. $P (R3 | G1)=\frac{1}{5}$

b. $P (R6| G3)= \frac{1}{3}$

c. $P(G3|E)=\frac{2}{3}$

d. $P (E|G3)=\frac{2}{3}$

Step-by-step explanation:

The sample space associated with the random experiment of throwing a dice is is the equiprobable space {R1, R2, R3, R4, R5, R6}. Then,

a. The conditional probability that 3 is rolled given that the roll is greater than 1? $P (R3 | G1) = \frac{P (R3\bigcap G1)}{P(G1)} = \frac{1/6}{5/6} = \frac{1}{5}$

b. What is the conditional probability that 6 is rolled given that the roll is greater than 3? $P (R6| G3) = \frac{P (R6\bigcap G3)}{P(G3)} = \frac{1/6}{3/6} = \frac{1}{3}$

c. What is P [GIE], the conditional probability that the roll is greater than 3 given that the roll is even? $P(G3|E) = \frac{P (G3\bigcap E)}{P(E)} = \frac{2/6}{3/6} = \frac{2}{3}$

d. Given that the roll is greater than 3, what is the conditional probability that the roll is even? $P (E|G3) = \frac{P (E\bigcap G3)}{P(G3)} = \frac{2/6}{3/6} = \frac{2}{3}$

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3 years ago

ANSWER NOW!! QUICKLY (EASY)

elena55 [62]

Answer:

2,640 ft

Step-by-step explanation:

You first find the difference between the two distances, 0.5 miles. One mile is 5280 feet, so

0.5 x 5280 = 2640

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3 years ago

In the city of Carmen, there is a drawbridge that is opened twice per hour over the summer. The graph below shows the number of

n200080 [17]

Answer:

1) Between 0 and 1 minute the rate of change is 25 ft./min

2) Between 1 and 2 minute the rate of change is 0 ft./min

3) Between 2 and 4 minute the rate of change is -12.5 ft./min

Step-by-step explanation:

1) Between 0, and 1 feet, we have;

The rate of change = (Final height - Initial height)/(Final time - Initial time)

The rate of change = (40 - 15)/(1 - 0) = 25 ft/min

Between 0 and 1 minute the rate of change = 25 ft./min

2) Between 1, and 2 feet, we have;

The rate of change = (40 - 40)/(2 - 1) = 0 ft/min

Between 1 and 2 minute the rate of change = 0 ft./min

3) Between 2, and 4 feet, we have;

The rate of change = (15 - 40)/(4 - 2) = -12.5 ft/min

Between 2 and 4 minute the rate of change = -12.5 ft./min

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3 years ago