Answer:
512
Step-by-step explanation:
8 = 2^3
Therefore,
8^3
= (2^3)^3
= 2^(3*3)
= 2^9
= 512
Thus, 8^3 = 512
<h2>Please mark my answer as Brainliest!!!</h2>
Answer:
19 yds
Step-by-step explanation:
On the assignment in the sections it tells you how to find it.
You worked a total of 35 hours that week.
4+3 is 7hours a day times 5 days which is 35.
Complete Question
The complete question is shown on the first uploaded image
Answer:
a
![g(h(x)) = \sqrt[4]{x^2 + x +5} + 3](https://tex.z-dn.net/?f=g%28h%28x%29%29%20%3D%20%5Csqrt%5B4%5D%7Bx%5E2%20%2B%20x%20%2B5%7D%20%2B%203)
b
![h(g(x)) = \sqrt{x} + 7\sqrt[4]{x} + 17](https://tex.z-dn.net/?f=h%28g%28x%29%29%20%20%3D%20%5Csqrt%7Bx%7D%20%20%2B%207%5Csqrt%5B4%5D%7Bx%7D%20%2B%2017)
c
![h(h(x)) = [x^2 + x + 5 ]^2 + x^2 + x + 10](https://tex.z-dn.net/?f=h%28h%28x%29%29%20%3D%20%20%5Bx%5E2%20%2B%20x%20%2B%205%20%5D%5E2%20%2B%20x%5E2%20%2B%20x%20%2B%2010)
Step-by-step explanation:
From the question we are told that

and
![g(x) = \sqrt[4]{x} + 3](https://tex.z-dn.net/?f=g%28x%29%20%3D%20%5Csqrt%5B4%5D%7Bx%7D%20%2B%203)
Considering first question
Now we are told g(h(x))
i.e
![g(h(x)) = [x^2 + x + 5 ]^{\frac{1}{4} } + 3](https://tex.z-dn.net/?f=g%28h%28x%29%29%20%3D%20%20%5Bx%5E2%20%2B%20x%20%2B%205%20%5D%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%20%2B%203)
=> ![g(h(x)) = \sqrt[4]{x^2 + x +5} + 3](https://tex.z-dn.net/?f=g%28h%28x%29%29%20%3D%20%5Csqrt%5B4%5D%7Bx%5E2%20%2B%20x%20%2B5%7D%20%2B%203)
Considering second question
Now we are told h(g(x))
i.e
![h(g(x)) = [x^{\frac{1}{4} } + 3]^2 + x^{\frac{1}{4} } + 3 + 5](https://tex.z-dn.net/?f=h%28g%28x%29%29%20%3D%20%20%5Bx%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%20%2B%203%5D%5E2%20%2B%20%20x%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%20%2B%203%20%2B%205)
=> 
=> 
=> ![h(g(x)) = \sqrt{x} + 7\sqrt[4]{x} + 17](https://tex.z-dn.net/?f=h%28g%28x%29%29%20%20%3D%20%5Csqrt%7Bx%7D%20%20%2B%207%5Csqrt%5B4%5D%7Bx%7D%20%2B%2017)
Considering third question
![h(h(x))= [x^2 + x + 5]^2 + [x^2 + x + 5 ] + 5](https://tex.z-dn.net/?f=h%28h%28x%29%29%3D%20%5Bx%5E2%20%2B%20x%20%2B%205%5D%5E2%20%2B%20%5Bx%5E2%20%2B%20x%20%2B%205%20%5D%20%2B%20%205)
=> ![h(h(x)) = [x^2 + x + 5 ]^2 + x^2 + x + 10](https://tex.z-dn.net/?f=h%28h%28x%29%29%20%3D%20%20%5Bx%5E2%20%2B%20x%20%2B%205%20%5D%5E2%20%2B%20x%5E2%20%2B%20x%20%2B%2010)