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yanalaym [24]
3 years ago
5

Marna is playing a game where you score -5 points each time you guess the correct answer. The goal is to get the lowest score. T

o win the game, Marna must have a score less than -80 points. How many correct answers does Marna need to win the game? Write an inequality.
Mathematics
1 answer:
Mice21 [21]3 years ago
7 0
74 points she would have to answer.
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According to records from 50 years, there is a 2/3 chance of June temperatures being above 80 F. Azul needs to find the probabil
Brrunno [24]

Record of june temperature of last 50 years

Probability of June temperature being above 80° F from last 50 years

                      =\frac{2}{3}

It means , out of 30 days ,there are  only 20 days , in which temperature is above 80°F.

⇒Probability that it will be above 80° F for 20 or more days this June

                =\frac{20+x}{30}  

where, x is the number of extra days after 20 days in month of june, when temperature is above 80°F.

Value of this Probability will be in between

                \frac{2}{3}\leq P \leq 1  

Now, what Azul wants

 To find the probability that it will be above 80° F for 20 or more days this June.

The Simulation given is

  ⇒There are 30 days in June. If we use a number cube with the numbers 1-6 and assign 1-4 as a temperature above 80° F and 5-6 as a temperature 80° F or below.

Total number of numbers on number cube ={1,2,3,4,5,6}

Favorable Outcome={1,2,3,4}=Temperature above 80° F

Temperature 80° F or below ={5,6}

⇒Probability of getting number {1,2,3,4} on the number cube when rolled once,that is Temperature above 80° F

        =\frac{4}{6}\\\\=\frac{2}{3}

⇒Probability of getting number {5,6} on the number cube when rolled once, that is Temperature 80° F or below

        =\frac{2}{6}\\\\=\frac{1}{3}

This is Incorrect Simulation, as there are chances that , there can be more than 20 days out of 30 days when Temperature goes above 80° F.But Here we have got Probability of temperature being above 80° F for 20 days only, not more than 20 days, which is =\frac{2}{3}

Not,a number

    \frac{2}{3}< \text{Probability} \leq 1.    

4 0
3 years ago
Does anybody know this?
vagabundo [1.1K]

Answer:

  see attached

Step-by-step explanation:

Reflection in the line y=1 is accomplished by the transformation ...

  (x, y) ⇒ (x, 2 -y)

Each point in the image is as far below the line as the original point is above the line.

6 0
2 years ago
Use the distributive property to find the price. 5($5.91) a. $30.45 b. $29.55 c. $25.50
enot [183]

5*5 = 25

5*9= 45

5*1= 5

25 dollars now add the cents

now it is $25.50

6 0
3 years ago
Read 2 more answers
What is the mean of the data set that is represented by this data plot?
const2013 [10]

Answer:

90

Step-by-step explanation:

4 0
2 years ago
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Evaluate using <br> Definite integrals
swat32

Since [0,4]=[0,1]\cup(1,4], we can rewrite the integral as

\displaystyle \int_0^1f(t)\;dt + \int_1^4 f(t)\; dt

Now there is no ambiguity about the definition of f(t), because in each integral we are integrating a single part of its piecewise definition:

\displaystyle \int_0^1f(t)\;dt = \int_0^11-3t^2\;dt,\quad \int_1^4 f(t)\; dt = \int_1^4 2t\; dt

Both integrals are quite immediate: you only need to use the power rule

\displaystyle \int x^n\;dx=\dfrac{x^{n+1}}{n+1}

to get

\displaystyle \int_0^11-3t^2\;dt = \left[t-t^3\right]_0^1,\quad \int_1^4 2t\; dt = \left[t^2\right]_1^4

Now we only need to evaluate the antiderivatives:

\left[t-t^3\right]_0^1 = 1-1^3=0,\quad \left[t^2\right]_1^4 = 4^2-1^2=15

So, the final answer is 15.

4 0
3 years ago
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