Question 1 2 pts Logic Puzzle: A certain clock runs fast; it indicates that 1 hour has passed when actually only 56 minutes have
1 answer:
Using proportions, it is found that the correct time when it reads 10:30pm is of 9:40 pm.
<h3>What is a proportion?</h3>A proportion is a fraction of total amount, and the measures are related using a rule of three.
In this problem, when 56 minutes have passed, the clock indicates that 60 minutes have passed. Hence, what is the time passed when the clock indicates that 12 hours and 30 minutes, that is, 60 x 12 + 30 = 750 minutes have passed?
Hence, the <em>rule of three</em> is:
56 minutes - 60 minutes
x minutes - 750 minutes
Applying cross multiplication:
700 minutes is 660/60 = 11 hours + 40 minutes after 10:00 am, hence the correct time is of 9:40 pm.
You can learn more about proportions at brainly.com/question/24372153
You might be interested in
I wonder if you mean to write in place of
...
If you meant what you wrote, then we have
If you meant to write (the cube root of 256), then we could go on to have
Gg easy
remember
(x^m)/(x^n)=x^(m-n)
and
(x^m)^n=x^(mn)
and
(xyz)^m=(x^m)(y^m)(z^m)
and
(m/n)^a=(m^a)/(n^a)
and
x^-n=1/(x^n)
so
=
=
=
=
=
remember
(x^m)/(x^n)=x^(m-n)
and
(x^m)^n=x^(mn)
and
(xyz)^m=(x^m)(y^m)(z^m)
and
(m/n)^a=(m^a)/(n^a)
and
x^-n=1/(x^n)
so