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Alex787 [66]
2 years ago
10

When a figure rotates around a point, this point is called the

Mathematics
2 answers:
VikaD [51]2 years ago
8 0
The answer is: D - center of rotation
maxonik [38]2 years ago
7 0

Answer:

Your answer is D. center of rotation!

Step-by-step explanation:

A rotation is a transformation in a plane that turns every point of a figure through a specified angle and direction about a fixed point. The fixed point is called the center of rotation . The amount of rotation is called the angle of rotation and it is measured in degrees.

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Find the equation of the line that passes through the point left-parenthesis 1 comma 8 right-parenthesis and is perpendicular to
Furkat [3]

Don't be shy about using actual parentheses and commas.

Line through (1,8) perpendicular to    

-\dfrac 4 5 x + \dfrac 5 4 y = -4

The perpendicular family is gotten by swapping the coefficients on x and y, negating exactly one of them.   The constant is given directly by the point we're through:

\dfrac 5 4 x + \dfrac 4 5 y = \dfrac 5 4 (1) + \dfrac 4 5 (8) = \dfrac 5 4 + \dfrac{32}{5}

Let's clear the fractions by multiplying both sides by 20.

25x + 16y = 25 + 128 = 153

Might as well stop here.

Answer: 25 x + 16 y = 153


7 0
3 years ago
K - 5 = 3/14<br><br> A) k = 4 1/14<br> B) k = 5 3/14<br> C) k = 5 2/9
Harman [31]
The answer to the question is B.
8 0
4 years ago
Read 2 more answers
Orange M&amp;M’s: The M&amp;M’s web site says that 20% of milk chocolate M&amp;M’s are orange. Let’s assume this is true and set
SOVA2 [1]

Answer:

The correct option is (A).

Step-by-step explanation:

Let <em>X</em> = number of orange  milk chocolate M&M’s.

The proportion of orange milk chocolate M&M’s is, <em>p</em> = 0.20.

The number of candies in a small bag of milk chocolate M&M’s is, <em>n</em> = 55.

The event of an milk chocolate M&M being orange is independent of the other candies.

The random variable <em>X</em> follows a Binomial distribution with parameter <em>n</em> = 55 and <em>p</em> = 0.20.

The expected value of a Binomial random variable is:

E(X)=np

Compute the expected number of orange  milk chocolate M&M’s in a bag of 55 candies as follows:

E(X)=np

         =55\times 0.20\\=11

It is provided that in a randomly selected bag of milk chocolate M&M's there were 14 orange ones, i.e. the proportion of orange milk chocolate M&M's in a random bag was 25.5%.

This proportion is not surprising.

This is because the average number of orange milk chocolate M&M’s in a bag of 55 candies is expected to be 11. So, if a bag has 14 orange milk chocolate M&M’s it is not unusual at all.

All unusual events have a very low probability, i.e. less than 0.05.

Compute the probability of P (X ≥ 14) as follows:

P(X\geq 14)=\sum\limits^{55}_{x=14}{{55\choose x}0.20^{x}(1-0.20)^{55-x}}

                 =0.1968

The probability of having 14 or more orange candies in a bag of milk chocolate M&M’s is 0.1968.

This probability is quite larger than 0.05.

Thus, the correct option is (A).

4 0
3 years ago
Find missing angles and variables
shutvik [7]

Answer:

e= 2x-4  

Step-by-step explanation:

the opposite of e is 2x-4.

7 0
4 years ago
Can I get some help im stuck???
svetoff [14.1K]
Connor
Initial Value=200ft
Rate of Change=10ft/min

Pilar
Initial Value=242ft
Rate of Change=8ft/min
6 0
3 years ago
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