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algol13
2 years ago
13

University graduates have a mean job search time of 38.1 weeks, with a standard deviation of 10.1 weeks. The distribution of job

search times is not assumed to be symmetric. Between what two search times does Chebyshev's Theorem guarantee that we will find at least 89% of the graduates
Mathematics
1 answer:
Lera25 [3.4K]2 years ago
5 0

Answer:

7.1 weeks to 68.4 weeks

Step-by-step explanation:

Chebyshev's Theorem states that:

75% of the measures are within 2 standard deviations of the mean.

89% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 38.1

Standard deviation = 10.1

Between what two search times does Chebyshev's Theorem guarantee that we will find at least 89% of the graduates

Between 3 standard deviations of the mean.

So from 38.1 - 3*10.1 = 7.8 weeks to 38.1 + 3*10.1 = 68.4 weeks

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Answer:

Length of base DE = 24 units

Step-by-step explanation:

Given:

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SO,

Perpendicular of given triangle = 32 unit

Hypotenuse of given triangle = 40 unit

Find:

Length of base DE

Computation:

Using Pythagoras theorem

Base = √Hypotenuse² - Perpendicular²

Length of base DE = √Hypotenuse of given triangle² - Perpendicular of given triangle²

Length of base DE = √40² - 32²

Length of base DE = √1,600 - 1,024

Length of base DE = √576

Length of base DE = 24 units

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2 years ago
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Each child would get $8.00.

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Sum of two numbers is 84. If one of the numbers exceeds the other by 12, the numbers are
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Answer:

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Step-by-step explanation:

since the correlation between the FFQ and DR is 0.89

      x                            y               xy                    x^{2}                            y^{2}

    8.26                      1.68          13.8768          68. 2276          2.8224

     0.83                      0               0                    06889                  0

     20.13                   15.1           303.963          405.2169          228.01

      11.16                   7.49          83.5884          124.5456           56.1001

      7.18                    12.84         92.1912            51.5524            164.8656

       1.76                       0                0                   3.0976                 0

     22.46                  25.06        567.8596        513.4756           628.0036

-----------------------------------------------------------------------------------------------------------

       ∑x_{i} =                 ∑y_{i} =              ∑x_{i} y_{i}=               ∑x_{i}^{2} y_{i}^{2}=             ∑y_{i} ^{2}=      

      71.98                   62.17         1061.479            1166.8046      1079.8017  

-------------------------------------------------------------------------------------------------------------

Correlation Coefficient or Pearson Correlation is given by:  

the rest calculation is in the attached image

3 0
3 years ago
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