<h2>
Maximum area is 25 m²</h2>
Explanation:
Let L be the length and W be the width.
Aidan has 20 ft of fence with which to build a rectangular dog run.
Fencing = 2L + 2W = 20 ft
L + W = 10
W = 10 - L
We need to find what is the largest area that can be enclosed.
Area = Length x Width
A = LW
A = L x (10-L) = 10 L - L²
For maximum area differential is zero
So we have
dA = 0
10 - 2 L = 0
L = 5 m
W = 10 - 5 = 5 m
Area = 5 x 5 = 25 m²
Maximum area is 25 m²
Answer:
191.5
Step-by-step 103.5 explanation:
295 x 0.35(which is 35%) = 103.5
295 - 103.5 = 191.5
hope this helps
Answer:
The slope of line q is
.
Step-by-step explanation:
We know that line p has a slope of
, and that line p and line q are parallel. Parallel lines always have the same slope. Thus, the slope of line q must be
as well.
Answer:
What’s the question
Step-by-step explanation:
1/4g = 1/2h 1/2g = 1h 2h = 1g 3h = 1 1/5 g
Hope this helps + hopes this is correct