For the answer to the question above,
2x^4 + 22x^3 + 60x^2
<span>GCF: 2x^2 </span>
<span>2x^2(x^2 + 11x + 30) =
So the following factor for the problem above is
2x^2(x + 6)(x + 5)
</span>
If you want to double check, just multiply the answer.
I hope my answer helped you.
the correct question in the attached figure<span>
we know that
</span>the probability
that a witness picks a particular person by chance-----> P=1/5
the probability
that all 7 witnesses would pick the same person-----> P=1/5^7=0.0000128
the answer is the option B 0.0000128
<span>There are a variety of problems in which the number of witnesses change, for example
</span><span>....find the probability that all
9 witnesses would pick the same person
</span>in this case, the probability would be-------> P=1/5^9=0.000000512<span>
</span>
Answer:
27 Palindromes are possible in the given situation.
Step-by-step explanation:
As a palindrome is a number that reads the same forward and backward and in our case, it is a 5 digit palindrome.
Let's suppose the 5 digit palindrome is ABCBA:
As we know that the digits on 4th and 5th positions will be the same as the digits on 1st and 2nd positions.
- The number of possibilities that a digit can come on 1st position are 3
- The The number of possibilities that a digit can come on 2nd position are 3
- The number of possibilities that a digit can come on 3rd position are 3
So the total number of possibilities that we can get 5 digit palindromes from digits 1, 2 and 3 are:
= 3 x 3 x 3
Total Palindromes = 27
yo sup??
as mentioned earlier XUY is simply the summation of all the unique elements of X and Y
S=XUY
={-1,0,1,2,5}
Therefore your answer is option 1 ie
1.{-1,0,1,2,5}
Hope this helps.
20 + (0.4 × 15) + 12 + (0.4 × 10) = 20 + 6 + 12 + 4 = 42
20 + 15 + 12 + 10 = 57
57 - 42 = 15
15 ÷ 57 × 100 = 1500 ÷ 57 = 26.3
Ans = $42.00, 26% off ...