(5, 12) e (-10, -3)
x.......y...1
5.....12..1
-10..-3..1

12x -10y -15 + 120 -5y + 3x = 0
12x + 3x - 10y - 5y - 15 + 120 = 0
15x - 15y + 105 = 0 :(5)
3x - 5y + 21 = 0
m = -a/b
m = -3/-5
m(5) = 3/5

y-yo = m(x-xo)
y-14 = 3/5*(x-7)
y-14 = 3x/5 - 7/5
3x/5 - y + 14 - 7/5 = 0
3x/5 - 5y/5 + 70/5 - 7/5 = 0
3x - 5y + 70 - 7 =0
3x - 5y + 63 = 0
m(s) = -3/-5 = 3/5

m(r) = m(s) --> são paralelas

7 0

3 years ago

Read 2 more answers

really need help on these two questions for geometry, please actually answer it instead of just grabbing points and leaving :')

zhuklara [117]

Answer:

Step-by-step explanation:

E and F are horizontally aligned, so the slope of EF is 0 and its length is 16-10 = 6.

G and H are horizontally aligned, so the slope of GH is 0 and its length is 16-10 = 6.

F and G are vertically aligned, so FG is vertical and its length is 10-4 = 6.

E and HG are vertically aligned, so EH is vertical and its length is 10-4 = 6.

Quadrilateral EFGH is a square.

8 0

3 years ago

4<br>-5a+b=8<br>7a +9b = -32<br>I need to use substitution for this one. Help?

Sauron [17]

Answer:

Step-by-step explanation:

$\left\{\begin{array}{ccc}-5a+b=8&\text{add}\ 5a\ \text{to both sides}\\7a+9b=-32\end{array}\right\\\\\left\{\begin{array}{ccc}b=5a+8&(1)\\7a+9b=-32&(2)\end{array}\right\\\\\text{Substitute (1) to (2):}\\\\7a+9(5a+8)=-32\qquad\text{use the distributive property}\\\\7a+(9)(5a)+(9)(8)=-32\\\\7a+45a+72=-32\qquad\text{subtract 72 from both sides}\\\\52a=-104\qquad\text{divide both sides by 52}\\\\\boxed{a=-2}\\\\\text{Put the value of}\ a\ \text{to (1):}\\\\b=5(-2)+8\\\\b=-10+8\\\\\boxed{b=-2}$

8 0

3 years ago